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almond37 [142]
3 years ago
10

144 divided by 8 distributive property

Mathematics
1 answer:
densk [106]3 years ago
3 0
18 just divide and add the distributive property after
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Number 3 please solve and explain
allochka39001 [22]

Answer: -12.5

Step-by-step explanation:

x(2y-3) and x=2.5 and y=-1

so you fix in the figures so it will turn to

2.5(-2-3)

so then you open the brackets with 2.5

-5-7.5

Answer: -12.5

8 0
4 years ago
Darcy uses place value blocks to show a number. She uses 4 thousand blocks and five hundereds blocks. What is the number? How ca
Maksim231197 [3]
Answer is 4,500. 4 1,000 blocks =4,000. 5x100 =500. 4,000 + 500 = 4,500.
4 0
3 years ago
Erica had 6 coins in her coin collection. she goes to a coin show and buys some coins. how many dose she have now?
Anuta_ua [19.1K]

Since, it is not given how many coins did Erica buy at the coin show, so, we can suppose that Erica bought "n" coins from the coin show.

Now, we know that Erica already had 6 coins in her coin collection before she went to the coin show and bought the "n" coins.

Therefore, the total number of coins that Erica will have in her possession after buying "n" coins from the coin show will be 6+n.


3 0
4 years ago
The length of the base of a scalene triangle is 22 meters and the height is 14 meters. Find the area of the scalene triangle
Nezavi [6.7K]

Answer:

Area is 154 square meters

Step-by-step explanation:

Well lets think about this

If I take a rectangle and cut it into half diagonally I would get 2 triangles right?

So if I have 2 triangles of the same height and base I can make a rectangle

to find the area of a rectangle I do length times width

So lets take our scalene triangle and multiply our base with its width and then divide by 2

22*14 = 308

308/2 is 154

5 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
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