Ask question

Ask question

All categories

3 years ago

8

UPLI Given f(x) = -2x - 12, find x when f(x) = 20.

1 answer:

mihalych1998 [28]3 years ago

8 0

Answer:

x = -16

Step-by-step explanation:

Set -2x - 12 = to 20 and solve for x:

Adding 12 to both sides, we get -2x = 32, so that x = -16

You might be interested in

What is the volume of a hemisphere with a diameter of 6.1 cm, rounded to the nearest tenth of a cubic centimeter?

Vladimir [108]

Answer:

The volume of hemisphere is V = 59.4 $cm^{3}$

Step-by-step explanation:

Diameter of hemisphere = 6.1 cm

Radius of hemisphere = 3.05 cm

We know that volume of hemisphere is given by

$V = \frac{2}{3} \pi r^{3}$

$V = \frac{2}{3} \pi (3.05)^{3}$

V = 59.4 $cm^{3}$

Therefore the volume of hemisphere is V = 59.4 $cm^{3}$

8 0

3 years ago

Read 2 more answers

What are irrational numbers *PLZ GIVE AN EXAMPLE*

Temka [501]

Irrational numbers have a long amount of numbers after the decimal place that never really end it would be like pi or the square root of two. Also irrational numbers can't be represented as a fraction

3 0

4 years ago

Two gears are adjusted so that the smaller gear drives the larger one. if the smaller gear of 3.7cm rotates through an angle of

zepelin [54]

Answer:

<em>The larger gear will rotate through 156°</em>

Step-by-step explanation:

<u>Arc Length</u>

The arc length S of an angle θ on a circle of radius r is:

$S = \theta r$

Where θ is expressed in radians.

The smaller gear of r1=3.7 cm drives a larger gear of r2=7.1 cm. The smaller gear rotates through an angle of θ1=300°.

Convert the angle to radians:

$\displaystyle \theta_1=300*\frac{\pi}{180}=\frac{5\pi}{3}$

The arc length of the smaller gear is:

$\displaystyle S_1=\frac{5\pi}{3}\cdot 3.7$

$\displaystyle S_1=\frac{18.5\pi}{3}$

The larger gear rotates the same arc length, so:

$\displaystyle S_2=\frac{18.5\pi}{3}$

$\displaystyle \theta_2\cdot r_2=\frac{18.5\pi}{3}$

Solving for θ2:

$\displaystyle \theta_2=\frac{18.5\pi}{3r_2}$

$\displaystyle \theta_2=\frac{18.5\pi}{3*7.1}$

$\theta_2=2.73\ radians$

$\displaystyle \theta_2=2.73*\frac{180}{\pi}=156$

The larger gear will rotate through 156°

7 0

3 years ago

Find the least common multiple of x3 - x2 + x - 1 and x2 - 1. Write the answer in factored form. A. (x + 1)2(x - 1) B. (x + 1)(x

WINSTONCH [101]

Hello,
Answer B

$x^3-x^2+x-1=(x-1)(x^2+1)\\
x^2-1=(x+1)(x-1)\\
lcm=(x-1)(x+1)(x^2+1)\\
$

8 0

4 years ago

Read 2 more answers

(m3 - 6m2 - 16m + 63) divided by (m - 7)

Arlecino [84]

Therefore( $m^3 -6m^2-16m +63$ )÷ (m-7) $= (m^2 +m-9)$

Step-by-step explanation:

$m^3 -6m^2-16m +63$

$=m^3 -7m^2$ $+m^2 -7m$ $-9m+63$

$= m^2(m-7)$ $+m(m-7)$ $-9(m-7)$

$= (m-7 ) (m^2 +m-9)$

Therefore( $m^3 -6m^2-16m +63$ )÷ (m-7) $= (m^2 +m-9)$

3 0

4 years ago