i need to know how to find the x and y intercepts and then graph the linear equation for the problem x+y=2

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

8 0

Answer:

The x-intercept of the straight line is at (2,0) and the y-intercept is at (0,2).

Join those two points with a straight line and get the graph.

Step-by-step explanation:

The intercept form of a straight line equation is $\frac{x}{a} + \frac{y}{b} = 1$ , where the x-intercept of the line is at (a,0) and the y-intercept will be at (0,b).

So, we have to arrange the equation of a straight line in the intercept form and then we can easily find the x-intercept and y-intercept of the line.

Given equation is x + y = 2

⇒ $\frac{x}{2} + \frac{y}{2} = 1$

Therefore, the x-intercept of the straight line is at (2,0) and the y-intercept is at (0,2).

Now, locate the two points as obtained on the graph and join them with a straight line and you will get the graph of the line. (Answer)

You might be interested in

The position s(t) of a robot moving along a track at time t is given by s(t)=9t^2−90t+4.

Xelga [282]

The total distance traveled by the robot from t=0 to t=9 is 1422 units

Integration is a way in which smaller components are brought together in pieces to form a whole. Integration can be used in finding areas, volumes and so on.

Given that the position s(t) at any time t is given by the function:

s(t)=9t²−90t+4

The total distance traveled by the robot from t=0 to t=9 can be gotten by integrating the position function within the limits 0< t < 9

Therefore:

$Total\ distance = \int\limits^9_0 {s(t) \, dt \\\\Total\ distance = \int\limits^9_0 {(9t^2-90t+4) \, dt\\\\Total\ distance = [3t^3-45t+4t]_0^9\\\\Total\ distance=-1422\ units$