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Galina-37 [17]
4 years ago
14

A production manager tests 10 batteries and finds that their mean lifetime is 468 hours. She then designs a sales package for th

is type of battery. It states that consumers can expect the battery to last approximately 500 hours. This is an example of what phase of inferential statistics? A.Probability-based inference B.Data organization C.Data gathering
Mathematics
2 answers:
AnnZ [28]4 years ago
7 0

Answer:

A.Probability-based inference

Step-by-step explanation:

Inferential statistics uses a random sample of data from a population to draw inferences about the population. One can make generalizations about a population.

The answer as per scenario is A.Probability-based inference.

The manager made an inference based on probability.

Usimov [2.4K]4 years ago
6 0

iits probalty like based analyse

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What am i supposed to type here tho, just look at the photo pls
Rus_ich [418]

slope is just "how much up or down" for one step to the right.

its clearly negative here

only -3 seems to be remotely plausible looking at the graph in your screenshot

5 0
3 years ago
Read 2 more answers
Stem of Equations<br> Substitute (2, 1) into x + 3y = 5 to get<br> =
algol [13]

Answer:

see below!!

Step-by-step explanation:

x + 3y = 5,

y = –x + 3

Substitute the point into each equation and verify that it is true

x + 3y = 5,  2 +3(1) = 5   5 = 5  true

y = -x +3    1 = -2+3     1=1  true

(2,1) is a solution

6 0
2 years ago
out of all the 59 candidate who sat for examination 35 did physics 35 also did mathematics while 28 also attempted biology. If 1
alisha [4.7K]
This doesn’t make sense
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5 0
3 years ago
A = bh/2 solve for b
rjkz [21]
A =  \dfrac{bh}{2}

Cross multiply:
2A = bh

Divide by h on both sides:
b =  \dfrac{2A}{h}
8 0
3 years ago
Can someone help me solve this differentiation/tangent problem?
nirvana33 [79]
A)

\bf g'(x)=\stackrel{product~rule}{2x\cdot f(x)+x^2\cdot  f'(x)}\quad &#10;\begin{cases}&#10;x=5\\&#10;f(5)=5\\&#10;f'(5)=5&#10;\end{cases}&#10;\\\\\\&#10;g'(5)=2(5)\cdot f(5)+(5)^2\cdot f'(5)\implies g'(5)=50+500\\\\\\ g'(5)=550\\\\&#10;-------------------------------\\\\&#10;g(5)=(5)^2f(5)\implies g(5)=125&#10;\\\\\\&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}&#10;\begin{cases}&#10;x=5\\&#10;y=125\\&#10;\stackrel{m}{g'(5)}=550&#10;\end{cases}\implies y-125=550(x-5)&#10;\\\\\\&#10;y-125=550x-2750\implies y=550x+400



b)

\bf h'(x)=\stackrel{quotient~rule}{\cfrac{f'(x)(x-6)~~-~~f(x)\cdot 1}{(x-6)^2}}\quad &#10;\begin{cases}&#10;x=5\\&#10;f(5)=5\\&#10;f'(5)=5&#10;\end{cases}&#10;\\\\\\&#10;h'(5)=\cfrac{f'(5)(5-6)~~-~~f(5)\cdot 1}{(5-6)^2}&#10;\\\\\\&#10;h'(5)=\cfrac{5(-1)-5}{(-1)^2}\implies h'(5)=-10\\\\&#10;-------------------------------\\\\

\bf h(5)=\cfrac{f(5)}{5-6}\implies h(5)=\cfrac{5}{-1}\implies h(5)=-5&#10;\\\\\\&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\quad &#10;\begin{cases}&#10;x=5\\&#10;y=-5\\&#10;\stackrel{m}{-10}&#10;\end{cases}\implies y-(-5)=-10(x-5)&#10;\\\\\\&#10;y+5=-10x+50\implies y=-10x+45
3 0
4 years ago
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