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Galina-37 [17]
4 years ago
14

A production manager tests 10 batteries and finds that their mean lifetime is 468 hours. She then designs a sales package for th

is type of battery. It states that consumers can expect the battery to last approximately 500 hours. This is an example of what phase of inferential statistics? A.Probability-based inference B.Data organization C.Data gathering
Mathematics
2 answers:
AnnZ [28]4 years ago
7 0

Answer:

A.Probability-based inference

Step-by-step explanation:

Inferential statistics uses a random sample of data from a population to draw inferences about the population. One can make generalizations about a population.

The answer as per scenario is A.Probability-based inference.

The manager made an inference based on probability.

Usimov [2.4K]4 years ago
6 0

iits probalty like based analyse

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Given one factor, use division to find the remaining factors.
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Answer:

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Step-by-step explanation:Idk really

3 0
3 years ago
The price of an item is $45.00. After a discount, the price is $38.25. What is the percent of the discount?
9966 [12]

Answer:

=15

Step-by-step explanation:

45-x% *45=38.25

(-45) x/100=38.5-45

(-45)x/100=(-6.75)

x=6.75 * 100/45

=<u>15</u>

8 0
3 years ago
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Help pls with answer!!!Rewrite the function in the given form.
Elis [28]

Answer:

g(x) = \frac{-2}{x-1}+5\\\\

The graph is shown below.

=========================================================

Explanation:

Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

g(x) = \frac{5x-7}{x-1}\\\\g(x) = \frac{5x-5-2}{x-1}\\\\g(x) = \frac{(5x-5)-2}{x-1}\\\\g(x) = \frac{5(x-1)-2}{x-1}\\\\g(x) = \frac{5(x-1)}{x-1}+\frac{-2}{x-1}\\\\g(x) = 5+\frac{-2}{x-1}\\\\g(x) = \frac{-2}{x-1}+5

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).

-------------------------

Compare the equation g(x) = \frac{-2}{x-1}+5\\\\ to the form g(x) = \frac{a}{x-h}+k\\\\

We can see that

  • a = -2
  • h = 1
  • k = 5

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

  • (-1,6)
  • (0,7) .... y intercept
  • (1.4, 0) .... x intercept
  • (2, 3)
  • (3, 4)

Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.

7 0
3 years ago
In the following equation, "a" and "b" are both integers.
sergij07 [2.7K]

Answer:

the value of a is -7

Step-by-step explanation:

but theres no b values?

4 0
3 years ago
Solve the equation 6=2d/5 for d.
Yuri [45]

6 =  \frac{2d}{5}  \\ 6 \times 5 = 2d \\ 30 = 2d \\  \frac{30}{2}   = d \\  \boxed{15 = d}

3 0
3 years ago
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