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3 years ago

10

Samantha drove 440 km in 5 hours. She drove part of the way at 80 km/h and the rest at 100 km/h. What distance did she drive at

each speed?

1 answer:

jarptica [38.1K]3 years ago

5 0

Answer:

She drove 200km at 100km/hr and she drove 240km at 80km/hr

Step-by-step explanation:

2×100km/hr=200km and 80km/hr×3=240km/hr

200km+240km=440km

(2+3=5)

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P(t) = 2ť + 10<br> n(t) = 4<br> What’s the function (p+n) (t)?

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Answer:

$\boxed{\sf (p + n)(t) = 2t + 14}$

Given:

$\sf p(t) = 2t + 10 \\ \sf n(t) = 4$

To find:

$\sf (f + g)(x) = f(x) + g(x)$

Step-by-step explanation:

$\sf \implies(f + g)x = f(x) + g(x) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2t + 10) + ( 4) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2t + 10 + 4 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2t + 14$

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3 years ago

can someone help me understand this, please? For some reason my answer is correct but I need to understand how did I found the c

Morgarella [4.7K]

Answer with step-by-step explanation:

The way the question is worded, this actually shouldn't be correct. The correct answer should be $3:4$ .

Because the trapezoids are similar, we can find the ratio of their perimeters by actually just finding the ratio of their sides.

Why?

By definition, the corresponding sides of a polygon are in a constant proportion. The perimeter is simply the sum of all sides of the polygon. Since we're just adding the sides, the proportion will still be maintained.

Therefore, we'll just need to ratio of their corresponding sides. The only two corresponding sides that are marked are $\overline{RS}$ and $\overline{AB}$ .

The ratio of $\overline{RS}:\overline{AB}$ is $18:24\implies \boxed{3:4}$ .

The reason why it ideally should be $3:4$ and not $4:3$ is because the question states $RTSU\sim ABCD$ , which mentions $RSTU$ first, so our answer should follow this respective order. I believe you were marked right anyways because the specific order is not specified, but generally, you want to give your answer respectively by default.

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2 years ago

Find the base of a parallelogram with an area of 18 square inches and a height of 2 inches

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3 years ago

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Please someone help me...

laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

$\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \cot(6A) - \cot(2A) }$

<u>Using trigonometric </u><u>identities</u>

That's

<h3> $\cot(x) = \frac{1}{ \tan(x) }$ </h3>

<u>Rewrite the expression</u>

That's

$\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \frac{1}{ \tan(6A) } } - \frac{1}{ \frac{1}{ \tan(2A) } }$

We have

<h3> $- \frac{1}{ \tan(2A) - \tan(6A) } - \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{ \tan(6A) \tan(2A) } }$ </h3>

<u>Rewrite the second fraction</u>

That's

<h3> $- \frac{1}{ \tan(2A) - \tan(6A) } - \frac{ \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) }$ </h3>

Since they have the same denominator we can write the fraction as

$- \frac{1 + \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) }$

Using the identity

<h3> $\frac{x}{y} = \frac{1}{ \frac{y}{x} }$ </h3>

<u>Rewrite the expression</u>

We have

<h3> $- \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{1 + \tan(6A) \tan(2A) } }$ </h3>

<u>Using the trigonometric identity</u>

<h3> $\frac{ \tan(x) - \tan(y) }{1 + \tan(x) \tan(y) } = \tan(x - y)$ </h3>

<u>Rewrite the expression</u>

That's

<h3> $- \frac{1}{ \tan(2A -6A) }$ </h3>

Which is

<h3> $- \frac{1}{ \tan( - 4A) }$ </h3>

<u>Using the trigonometric identity</u>

<h3> $\frac{1}{ \tan(x) } = \cot(x)$ </h3>

Rewrite the expression

That's

<h3> $- \cot( - 4A)$ </h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3> $- ( - \cot(4A) )$ </h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2> $\cot(4A)$ </h2>

As proven

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3 years ago

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Triss [41]

Answer:

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