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vazorg [7]
4 years ago
10

Samantha drove 440 km in 5 hours. She drove part of the way at 80 km/h and the rest at 100 km/h. What distance did she drive at

each speed?
Mathematics
1 answer:
jarptica [38.1K]4 years ago
5 0

Answer:

She drove 200km at 100km/hr and she drove 240km at 80km/hr

Step-by-step explanation:

2×100km/hr=200km and 80km/hr×3=240km/hr

200km+240km=440km

(2+3=5)

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Solve the following systems of equations for x <br><br> 2x+3y=-14<br> Y= 6x+22
-Dominant- [34]
For the first one the answer is x = -3/2y - 7 and the second answer is x = 1/6y + -11/3
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Youre purchasing a new television with a 32" screen. the 32" measurement represents the diagonal measurement of the screen. You
Nonamiya [84]

Answer:

B. 28 inches

Step-by-step explanation:

We can use the Pythagorean theorem to solve this problem.

a^2 +b^2 =c^2  where a and b are the legs and c is the hypotenuse (diagonal)

16^2 + b^2 = 32^2

256 + b^2 =1024

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Rounding to the nearest inche

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3 0
3 years ago
In the expression -3×+4y-2 what are the variables
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7 0
3 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
1. (10pts] Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}. Determine each of the following (a) An Bn
alisha [4.7K]

Answer and explanation:

Given : Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}.

To find : Determine each of the following,

a) (A\cap B)\cap C

b) (A\cup B)\cap (A\cup C)

c) A - (B\cup C)

d) (A-C) (C-A)

Solution :

The union of two sets is a new set that contains all of the elements that are in at least one of the two sets.

The intersection of two sets is a new set that contains all of the elements that are in both sets.

a) (A\cap B)\cap C

A\cap B=\{1,4,5\}

Then, (A\cap B)\cap C=\{4\}

b) (A\cup B)\cap (A\cup C)

A\cup B=\{1,2,3,4,5,7,8,9\}

A\cup C=\{1,2,3,4,5,7,9\}

(A\cup B)\cap (A\cup C)=\{1,2,3,4,5,7,9\}

c) A - (B\cup C)

B\cup C=\{1,2,4,5,6,7,8,9\}

A - (B\cup C)=\{3\}

d) (A-C) (C-A)

A-C=\{1,3,5\}

C-A=\{6,7,9\}

(A-C) (C-A)=\{1,3,5\}\times\{6,7,9\}

(A-C) (C-A)=\{(1,6),(1,7),(1,9),(3,6),(3,7),(3,9),(5,6),(5,7),(5,9)\}

5 0
3 years ago
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