Since all the variables cancel out and the coefficient equal to eachother, this system of equation has <u>infinitely many solutions!</u>
5+25+125+625+3125+15625 rewrite each series using sigma notation
1 answer:
1. You have that the series is: <span>5+25+125+625+3125+15625
2. You must find the ratio (r) between the adjacent members. Then, you have:
25/5=5
125/25=5
625/125=5
3125/625=5
15625/3125=5
3. Therefore, the ratio is:
r=5
4. Then, each term has te form 5</span>^k. <span>So, you have:
5</span><span>^1=5
</span> 5<span>^2=25
</span> 5<span>^3=125
</span> 5<span>^4=625
</span> 5<span>^5=3125
</span> 5<span>^6=15625
5. As you can see, "k" goes from 1 to 6.
6. The answer is shown in the image attached.</span>
2. You must find the ratio (r) between the adjacent members. Then, you have:
25/5=5
125/25=5
625/125=5
3125/625=5
15625/3125=5
3. Therefore, the ratio is:
r=5
4. Then, each term has te form 5</span>^k. <span>So, you have:
5</span><span>^1=5
</span> 5<span>^2=25
</span> 5<span>^3=125
</span> 5<span>^4=625
</span> 5<span>^5=3125
</span> 5<span>^6=15625
5. As you can see, "k" goes from 1 to 6.
6. The answer is shown in the image attached.</span>
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Since all the variables cancel out and the coefficient equal to eachother, this system of equation has <u>infinitely many solutions!</u>
9p^2 - 6 = 642; / + 6 ;
9p^2 = 648; / ÷9 ;
p^2 = 72 ;
p = +
;
Finally, p = +6
or p = -6
9p^2 = 648; / ÷9 ;
p^2 = 72 ;
p = +
Finally, p = +6