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Ulleksa [173]
3 years ago
10

The answer to this question

Mathematics
1 answer:
oee [108]3 years ago
6 0
If the cell phone company charges a flat $40 fee monthly, then the equation would be y = 40.


The company does charge $40 a month, but also charges $2 per minute out of service area (x).

So the equation is y = 2x + 40

To graph this linear function, plug in values for x then plot the plots. Then draw a line to connect the points.

y = f(x)

f(0) = 40
f(1) = 42
f(2) = 44
f(3) = 46
f(4) = 48
f(5) = 50

So at x=0, draw a point at y=40 and so on.






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Dima020 [189]

Answer:

these nuts because xyz means examin your zipper so therefore these nuts need to be zipped up

3 0
3 years ago
Please help!! Giving brainliest and extra points! (Click on photo)
tamaranim1 [39]

Answer:

B, C and I think D

Step-by-step explanation:

5 0
3 years ago
The flight of a cannonball toward a hill is described by the parabola y=2+0.12x- 0.0004x^2
Stells [14]

The computation shows that the placw on the hill where the cannonball land is 3.75m.

<h3>How to illustrate the information?</h3>

To find where on the hill the cannonball lands

So 0.15x = 2 + 0.12x - 0.002x²

Taking the LHS expression to the right and rearranging we have:

-0.002x² + 0.12x -.0.15x + 2 = 0.

So we have -0.002x²- 0.03x + 2 = 0  

I'll multiply through by -1 so we have

0.002x² + 0.03x -2 = 0.

This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.

The second solution y = 0.15 * 25 = 3.75

Learn more about computations on:

brainly.com/question/4658834

#SPJ4

Complete question:

The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

6 0
2 years ago
................. plz let only deltaalex answer:) don’t trust anyone on here but them!
nevsk [136]

Answer:

Step-by-step explanation:

oh law of sines   soo  sin(A) / a = Sin(B) / b

2a)

here DE = side f   then let's find that side with law of sines and plug side f in as 'a' in law of sines , so

Sin(28) / a = Sin(54) / 31  ( where a = f = DE )

can you do the algebra here Emily?  or do you want me to show that?

Sin(28) *31 / Sin(54) = a

17.989 =a

18.0 =a       (rounded to nearest 10th)

DE = 18.0 m

2b)

find RT  where RT = side a

since they give use 2 of the other sides of the triangle we can quickly figure out the S angle.   180 = 71+62+S   so  S = 47°  ( I'm going kinda fast b/c I don't know how much time you have  :? )

then Sin(A) /a = Sin(B) / b

Sin(47) / a = Sin(62) / 29

Sin(47) *29 / Sin(62) = a

24.020 = a

RT = 24.0 meters  ( rounded to nearest 10th )

2c)

they want us to find ∠X with law of sines soo

I'll just use the letter they give us for variables

Sin(X) / x  = Sin(Y ) / y

Sin(X) = x* Sin(y) / y

X = arcSin [ 14 * Sin(108) / 34 ]

X = arcSin [ 0.3916115]

X = 23.0548°

X= 23°  ( rounded to nearest degree )

2d)

they ask us to find ∠E

I'll , again, use the letter they give us for variables

Sin(E) / e = Sin( F ) / f

Sin(E) / 18 = Sin(78) / 30

E = arcSin[ 18 * Sin(78) / 30 ]

E = arcSin [ 0.5868856 ]

E = 35.936 °

E = 36 °    ( rounded to nearest degree )

:)

3 0
3 years ago
Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS: A) cos E = 312 + 392 – 2(3
defon

This question is incomplete because the options were not properly written.

Complete Question

Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS:

A) cos E = 31²+ 39² – 2(31)(39)

C) 56² = 39² – 2(39) ⋅ cos E

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Answer:

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Step-by-step explanation:

From the above diagram, we see are told to apply the law of cosines to solve for m∠E i.e Angle E

The formula for the Law of Cosines is given as:

c² = a² + b² − 2ab cos(C)

Because we have sides d , e and f and we are the look for m∠E the law of cosines would be:

e² = d² + f² - 2df cos (E)

e = 56

d = 39

f = 31

56² = 39² + 31² - (2 × 39 × 31) × cos E

Therefore, from the above calculation and step by step calculation, the option that applies the law of cosines correctly and could be solved to find m∠E

Is option D: 56² = 31² + 39² – 2(31)(39) ⋅ cos E

8 0
4 years ago
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