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klasskru [66]
3 years ago
10

Of the 2,598,960 different five-card hands possible from a deck of 52 playing cards, how many would contain all black cards.

Mathematics
1 answer:
kumpel [21]3 years ago
3 0

Answer: 65,780

Step-by-step explanation:

When we select r things from n things , we use combinations and the number of ways to select r things = ^nC_r=\dfrac{n!}{(n-r)!r!}

Given : The total number of playing cards in a deck = 52

The number of different five-card hands possible from a deck = 2,598,960

In a deck , there are 26 black cards and 26 red cards.

The number of ways to select 5 cards from 26 cards = ^{26}C_{5}=\dfrac{26!}{(26-5)!5!}

=\dfrac{26\times25\times24\times23\times22\times21!}{21!(120)}=65780

Hence, the number of different five-card hands possible from a deck of 52 playing cards such that all are black cards = 65,780

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4 years ago
Ginny factored 6x2 – 31x – 30 as shown: ac = –180 and b = 31 36(–5) = –180 and 36 + (–5) = 31 6x2 + 36x – 5x – 30 6x(x + 6) – 5(
meriva

Answer:

Ginny made a mistake in step 1 when she identified b = 31. It should be b=-31

Step-by-step explanation:

Ginny factored 6x^2 -31x -30 as shown:

ac = –180 and

b = 31

36(–5) = –180 and 36 + (–5) = 31

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b is the coefficient of x and from the trinomial 6x^2 -31x -30, b=-31.

Therefore Ginny made a mistake in step 1 when she identified b = 31. It should be b = –31.

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6x^2-36x +5x -30  

6x(x-6)+5(x-6)

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Pavlova-9 [17]

Answer:

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Hope it helped!! plz mark brainliest!! have a good day !! :)

7 0
3 years ago
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