Ask question

Ask question

All categories

3 years ago

15

Steven goes to the grocery store and is looking at in Winter squash it has the mass of 1857 grams how many kilograms does the wi

nter squash weigh

1 answer:

steposvetlana [31]3 years ago

6 0

The answer is 1.857 since there is 1000 grams in a kilogram

You might be interested in

Can somebody help me with this?

N76 [4]

Rise is 35, run is 1
35 is the answer

8 0

3 years ago

Are these a rational function?

Thepotemich [5.8K]

158.:$?&duck icy blue

5 0

3 years ago

Explain how to estimate 524 divide 9

IgorC [24]

Once Youu Divide It Youu Go 524/9=58.222222... A lot Of 2's..
Hope This Helps Youu
Youur Welcome

6 0

3 years ago

Help!! Ill give 100 points!

Volgvan

Answer:

It will take about half an hour more for maria to finish his/her project than Juan.

Step-by-step explanation:

9/10 > 2/6

=> 54/60 > 20/60

=> 34/60

Therefore, it will take about half an hour more for maria to finish his/her project than Juan.

Hoped this helped.

5 0

3 years ago

Read 2 more answers

Help please!!!!!!!!!

In-s [12.5K]

ANSWER

24

EXPLANATION

For a matrix A of order n×n, the cofactor $C_{ij}$ of element $a_{ij}$ is defined to be

$C_{ij} = (-1)^{i+j} M_{ij}$

$M_{ij}$ is the minor of element $a_{ij}$ equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.

Here, we have

$C_{11} = (-1)^{1+1} M_{11} = M_{11}$

M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.

$\begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \end{aligned}$

Since the determinant of a 2×2 matrix is

$\det\left( \begin{bmatrix} a & b \\ c& d \end{bmatrix} \right) = ad-bc$

it follows that

$\begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}$

so $C_{11} = M_{11} = 24$

4 0

3 years ago