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sveta [45]
2 years ago
12

Use the distance formula to determine the distance points (-5,5) and (1,-3)

Mathematics
1 answer:
VikaD [51]2 years ago
8 0
For points (x1,y1) and (x2,y2)
D=\sqrt{(x2-x1)^2+(y2-y1)^2}

(-5,5)
(1,-3)
(x,y)
x1=-5
y1=5
x2=1
y2=-3

D=\sqrt{(x2-x1)^2+(y2-y1)^2}
D=\sqrt{(1-(-5))^2+(-3-5)^2}
D=\sqrt{(6)^2+(-8)^2}
D=\sqrt{36+64}
D=\sqrt{100}
D=10


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jek_recluse [69]
<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

Domain = [-3, infinity)

==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

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2 years ago
Evaluate -3(8).
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Answer:

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Step-by-step explanation:

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Because when ever you multiply a negative number with a positive number result will always be negative and 3 multiply 8 is 24.

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Read 2 more answers
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