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sveta [45]
3 years ago
12

Use the distance formula to determine the distance points (-5,5) and (1,-3)

Mathematics
1 answer:
VikaD [51]3 years ago
8 0
For points (x1,y1) and (x2,y2)
D=\sqrt{(x2-x1)^2+(y2-y1)^2}

(-5,5)
(1,-3)
(x,y)
x1=-5
y1=5
x2=1
y2=-3

D=\sqrt{(x2-x1)^2+(y2-y1)^2}
D=\sqrt{(1-(-5))^2+(-3-5)^2}
D=\sqrt{(6)^2+(-8)^2}
D=\sqrt{36+64}
D=\sqrt{100}
D=10


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1. The figure is a prism: V = lwh = (12.1)(5.3)(4.2) = 269.3 cu. cm.


2. The figure is also a prism but the base is triangular: V = 1/2*b*h*l = 1/2*(13)*(sqrt(3)/2*13)*24 = 1756.3 cu. yd.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

8 0
3 years ago
Help with my mathhh!
Allisa [31]

Answer:

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
I am having trouble with this ellipse problem. Please help right away​
Vitek1552 [10]

Answer:

a. The distance from the center to either vertex

Step-by-step explanation:

The distance from the center to a vertex is the fixed value <em>a</em>. The values of <em>a</em> and <em>c</em> will vary from one ellipse to another, but they are fixed for any given ellipse.

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

3 0
3 years ago
A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are
skelet666 [1.2K]

A) The maximum revenue is 450000$

B) The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

C) When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

A)p(x)=300−(x/20​),

revenue R(x)=p*x

revenue R(x)=300x -(x2/20)

for maximum revenue dR/dx =0 ,

=>300-(2x/20)=0

=>x/10=300

=>x=3000

maximum revenue = R(3000)=300*3000 -(30002/20)

maximum revenue = R(3000)=450000$

B) profit =revenue -cost

profit P(x)=300x -(x2/20)-72000-60x

profit P(x)=240x -(x2/20)-72000

for maximum cost dP/dx =0

240 -(2x/20)=0

x=240*10

x=2400

p(2400)=300−(2400/20​)=180

profit P(2400)=240*2400 -(24002/20)-72000 =216000

The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

c)

profit =revenue -cost -tax

profit P(x)=300x -(x2/20)-72000-60x-55x

profit P(x)=185x -(x2/20)-72000

for maximum cost dP/dx =0

185-(2x/20)=0

x=185*10

x=1850

p(1850)=300−(1850/20​)=207.5

profit P(1850)=185*1850 -(18502/20)-72000

profit P(1850)=99125$

When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

To know more about maximum profit check the below link:

brainly.com/question/4166660

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5 0
1 year ago
A. A game uses spinner A below. If a player spins a 1, he or she wins
rjkz [21]

Answer:

1/4

Step-by-step explanation:

There are 4 slot, he/she need 1 slot to win, so 1/4

3 0
3 years ago
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