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Nata [24]
3 years ago
12

Rewrite the radical expression as an expression with a rational exponent. the seventh root of x to the third power

Mathematics
2 answers:
kap26 [50]3 years ago
5 0

Answer:

yes, x to the 3/7th power is correct

Step-by-step explanation:

i just took the test today

kherson [118]3 years ago
4 0

The expression with a rational exponent of the seventh root of x to the third power is x to the three sevenths power ⇒ answer A

Step-by-step explanation:

Let us explain how to change the radical expression as an expression

with a rational exponent

1. Find the number of the root and make it the denominator of the

  fraction exponent

2. Find the power of the term under the radical and make it the

   numerator of the fraction exponent

Examples:

\sqrt{x^{n}}=x^{\frac{n}{2}}

\sqrt[3]{x^{n}}=x^{\frac{n}{3}}

\sqrt[5]{x^{n}}=x^{\frac{n}{5}}

So \sqrt[m]{x^{n}}=x^{\frac{n}{m}}

∵ the radical expression is the seventh root of x to the third power

∵ seventh root = \sqrt[7]{}

∵ x to the third power = x³

∴ seventh root of x to the third power = \sqrt[7]{x^{3}}

Let us change it to the rational exponent

∵ \sqrt[m]{x^{n}}=x^{\frac{n}{m}}

∵ \sqrt[7]{x^{3}}

∴ m = 7 and n = 3

∴ \sqrt[7]{x^{3}} = x^{\frac{3}{7}}

∵ x^{\frac{3}{7}} is x to the three sevenths power

∴ \sqrt[7]{x^{3}} is x to the three sevenths power

The expression with a rational exponent of the seventh root of x to the third power is x to the three sevenths power

Learn more:

You can learn more about radical equation is brainly.com/question/7153188

#LearnwithBrainly

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The number (x) that is (=) 10 less than (-) 6

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2 years ago
Can anyone help please? No links cause I can’t see them.
tamaranim1 [39]

Answer:

Step-by-step explanation:

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3 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

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Step-by-step explanation:

okay so -25 • -9 = 9+10

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