Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75
Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75
Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
Elaine's piece is bigger because when you look at the tenths place, you can see that 1 is bigger than 0.
I solved it on your other posting of it. x = 12
All of the steps are there
Answer:
12
Step-by-step explanation:
(-15)/(-18) = 10/x cross multiply expressions
-15x = -180 since both sides are negative we can write without the sign
15x = 180 divide both sides by 15
x = 12
The numerator factors as (t-8)(t+4), so the whole thing is (t-8)(t+4)/(t-8). Now we can cancel the t-8 AS LONG as t isn't equal to 8, otherwise, we are canceling a zero from both numerator and denominator which is invalid. What is left is t+4.
So your choice was right.
