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Olin [163]
3 years ago
12

A painting with dimensions 10 inches by 14 inches is placed in a picture frame (of constant width), increasing its area to 221 s

quare inches. How many inches is the width of the picture frame?
Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

1.5 inches

Step-by-step explanation:

(10+2x)(14+2x) = 221

4x² + 48x - 81 = 0

4x² + 54x - 6x - 81 = 0

2x(2x + 27) - 3(2x + 27) = 0

(2x + 27)(2x - 3) = 0

x = -27/2, 3/2

x = 3/2 or 1½ or 1.5 inches

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Answer:

The answer is

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Step-by-step explanation:

<h3>- 6 < 2x - 4 < 4</h3>

First of all add 4 to both sides of the inequality to make 2x stand alone

That's

<h3>- 6 + 4 < 2x - 4 + 4 < 4 + 4 \\  - 2 < 2x < 8</h3>

Divide both sides of the inequality by 2 inorder to find x

That's

<h3>\frac{ - 2}{2}  <  \frac{2x}{2}  <  \frac{8}{2}</h3>

We have the final answer as

<h3>- 1 < x < 4</h3>

Hope this helps you

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