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anyanavicka [17]
3 years ago
15

Which unit of measurement would be the most appropriate unit to measure the distance from the earth to the moon?

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

kilometer


Step-by-step explanation:


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If you help ill give you some of my banana milk...
snow_tiger [21]

Given:

The function is:

f(x)=4x^2-25x-21

To find:

The domain of the given function.

Solution:

Domain is the set of input values.

We have,

f(x)=4x^2-25x-21

It is a quadratic polynomial.

We know that a quadratic polynomial is defined for all real values of x. So, the given function is defined for all real values of x and the domain of the given function is:

Domain = Set of all real number

Domain = (-∞,∞)

Therefore, the correct option is B.

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What is the value of x in the equation 3X minus 4Y equals 65, when Y equals four
Vika [28.1K]

Answer:

Step-by-step explanation:

3x-4y=65

3x=65+4y

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Read 2 more answers
Evaluate the surface integral. s x ds, s is the part of the plane 18x + 9y + z = 18 that lies in the first octant.
IceJOKER [234]
In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.

(x,0,0)\implies 18x+9\cdot0+0=18\implies x=1
(0,y,0)\implies 18\cdot0+9y+0=18\implies y=2
(0,0,z)\implies 18\cdot0+9\cdot0+z=18\implies z=18

Now that we know the vertices of the surface \mathcal S, we can parameterize it by

\mathbf s(u,v)=\langle(1-u)(1-v),2u(1-v),18v\rangle

where 0\le u\le1 and 0\le v\le1. The surface element is

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=2\sqrt{406}(1-v)\,\mathrm du\,\mathrm dv

With respect to our parameterization, we have x(u,v)=(1-u)(1-v), so the surface integral is

\displaystyle\iint_{\mathcal S}x\,\mathrm dS=2\sqrt{406}\int_{u=0}^{u=1}\int_{v=0}^{v=1}(1-u)(1-v)^2\,\mathrm dv\,\mathrm du=\frac{\sqrt{406}}3
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3 years ago
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