All categories

3 years ago

Which of the following is the graph of y=- square root x+1

Mathematics

2 answers:

maks197457 [2]3 years ago

4 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$y=-\sqrt{x+1}$

Find the intercepts

<u>The y-intercept</u> is the value of y when the value of x is equal to zero

For x=0 -----> $y=-\sqrt{0+1}=-1$

The y-intercept is the point (0,-1)

<u>The x-intercept </u>is the value of x when the value of y is equal to zero

For y=0 -----> $0=-\sqrt{x+1}$ -----> $x=-1$

The x-intercept is the point (-1,0)

<em>Find the domain</em>

we know that

The radicand must be positive

$x+1\geq0$

$x\geq-1$

All real numbers greater than or equal to -1

The range is all real numbers less than or equal to -1

using a graphing tool

see the attached figure

Alexeev081 [22]3 years ago

3 0

Answer:

C: third graph picture is attached.

Step-by-step explanation:

You might be interested in

The Table represents a Linear Function.

ExtremeBDS [4]

Answer:

The answer is 3

Step-by-step explanation:

I used the equation y/x. (Use the differences between two rows.)

7 0

3 years ago

Who is bigger 0.17 or o.165

Zepler [3.9K]

So... 0.170
0.165.

So at first it was 0.17. But if you add that imaginary 0 its 0.170. So now the answer is 0.170. Hope this helps! ;)

3 0

3 years ago

Read 2 more answers

HELPPP PLS SHOW WORK

expeople1 [14]

Answer:

Step-by-step explanation:

1. let the unknown be x

2. using theorem of Pythagoras that states the hypotenuse will be equal to the sum of the other two sides we can determine that 75=14+X

3. this implies that X=75-14

4. therefore X= 61

7 0

2 years ago

Integrate the following:<br><img src="https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Cint%20%5C%3A%20%20%5Ctan%28x%29%20%20%20%5

Korvikt [17]

Answer:

$\huge \boxed{\red{ \boxed{ - \cos(x) + C}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

integration
PEMDAS

<h3>tips and formulas:</h3>

$\tan( \theta) = \dfrac{ \sin( \theta) }{ \cos( \theta) }$
$\sf \displaystyle \int \sin(x) \: dx = - \cos(x) + C$

<h3>let's solve:</h3>

$\sf \: rewrite \: \tan( \theta) \: as \: \dfrac{ \sin( \theta) }{ \cos( \theta) } : \\ = \displaystyle \int \: \frac{ \sin(x) }{ \cos(x) } \cos(x) \: dx \\ = \displaystyle \int \: \frac{ \sin(x) }{ \cancel{\cos(x) }} \: \cancel{ \cos(x)} \: dx \\ = \displaystyle \int \: \sin(x) \: dx$
$\sf \: use \: the \: formula : \\ \sf \displaystyle - \cos(x)$
$\sf add \: constant : \\ - \cos(x) + C$