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2 years ago

If a figure is dilated by a factor of 5/6 ,the perimeter of the figure will change by a factor of

Mathematics

2 answers:

fenix001 [56]2 years ago

6 0

Answer:

1,2,3,6

Step-by-step explanation:

6x1, 2x3, 3x2, 6x1

i study hard and work my hardest

Wittaler [7]2 years ago

4 0

Answer:

Step-by-step explanation:

The dilation will affect every side by a factor of 5/6

P = 2(w + l)

The perimeter of the image:

P' = 2(5/6w + 5/6l)= 5/6*2(w + l) = 5/6P

The factor will be same: 5/6

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12a^3b^2 +18a²b^2 – 12ab^2 Factor completely

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Solution:

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

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Taking $b^2$ as common term,

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Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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