A bag contains 4 white, 3 black, and 6 green balls. Balls are picked at random. Explain why the events picking a white ball and
then another white ball without replacement are dependent. Then, identify the probability. a. P(white) is different when it is known that a white ball has been picked already.
P(white and white) = 4/11
b. P(white) is the same when it is known that a white ball has been picked already.
P(white and white) = 1/12
c. P(white) is the same when it is known that a white ball has been picked already.
P(white and white) = 1/9
d. P(white) is different when it is known that a white ball has been picked already.
P(white and white) = 1/13
D is the correct answer because first of all, there are 13 balls total. So the denominator would have to be 13. Also, white is the second largest number of balls in the set, so it is pretty likely that you will pick it. Although the most common picked would be green since it has the most balls.
