Answer:
The correct answer is Adaptive differential pulse code modulation
Explanation:
Adaptive differential pulse code modulation (ADPCM) is a variant of differential pulse-code modulation (DPCM) that varies the size of the quantization step, to allow further reduction of the required data bandwidth for a given signal-to-noise ratio. The output data rate can be dynamically adjusted between 16 kbit/s and 64 kbit/s in these applications.
The answer is a Mesh topology. This method connects every device to each other device in the network. A wired full-mesh topology is not as common as it is impractical and highly expensive. A partial mesh topology offers redundancy if one of the connections goes down and usually uses a connecting medium such as a router to eliminate cables and expensive PCI NIC's.
Th answer to your question is Endpoint
Atleast a minimum of 3%. Brainliest?
Answer:
int SmallestNumber(int num1, int num2, int num3){
int smallest;
if (num1 >num2){
smallest=num2;
}
else {
smallest=num1;
}
if(smallest <num3){
smallest=num3;
}
}
int LargestNumber(int num1, int num2, int num3){
int largest;
if (num1 <num2){
largest=num2;
}
else {
largest=num1;
}
if(largest>num3){
largest=num3;
}
}
void main(){
int num1,num2,num3;
printf("enter values");
scanf("%d%d%d",&num1,&num2,&num3);
int smallest=SmallestNumber(num1,num2,num3);
int largest=LargestNumber(num1,num2,num3);
}
Explanation:
we are comparing first two numbers and finding largest among those. After getting largest comparing that with remaining if it is greater then it will be largest of three. Same logic applicable to smallest also
