Answer:
.
Step-by-step explanation:
In general, let
denote the center of a given circle. Let
denote the radius of that circle. The standard equation for that circle would be:
.
The circle in this question is centered at
.
is the
-coordinate of the center of this circle.
.
is the
-coordinate of the center of this circle.
.
The radius of this circle is
. Therefore,
.
Hence, the standard equation for this circle would be:
.
A) 125 mm3 v=bh
v=(5*5/2)*10
To isolate the variable means to get it by itself.