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Len [333]
3 years ago
10

If you know a car travels 30 km in 20 minutes you can find its

Mathematics
1 answer:
Daniel [21]3 years ago
8 0

Answer:

You can find its average speed.

Step-by-step explanation:

To find average speed you can divide distance by time which has been given.

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What is the value of y?
NNADVOKAT [17]

Answer:

b-65

Step-by-step explanation:

They give you 130 and so to get the next measure its 180-130 and you get 50. So the blank angle is 50. Then the next two angles are y which means theyre equal to each other so they have to be the same number. Get 180 again and subtract 50 and get 130. Split 130 in half and get 65.

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You should have ____ revolving credit lines. A. 3. B. 1 to 3. C. 2. D. 2 to 6
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Revolving credit lines open account credit offered by banks or other financial institutions.
You should have <span>2 to 6 </span>revolving credit lines.
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Who baked more cookies per batch?
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Jenny does, she bakes 12 for every x and dan bakes 10 for every x.
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Hi i have a science project i have to ask 50 people that when they see blue,white green turquoise yellow orange and red what do
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Alissa Barnes

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green-organic

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3 years ago
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Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on
Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

  • If he is given with two kings.
  • If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by =  \frac{^{3}C_2 }{^{47}C_2}   {∵ one king is already there}

              =  \frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}           {∵ ^{n}C_r = \frac{n!}{r! \times (n-r)!} }

              =  \frac{3}{1081}  =  0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =  \frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}

                                                                   =  \frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}

                                                                   =  \frac{6}{1081}  =  0.0055

Now, probability that he ends up with a full house = \frac{3}{1081} + \frac{6}{1081}

                                                                                    =  \frac{9}{1081} = <u>0.0083</u>.

3 0
3 years ago
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