Wes lives in Colorado, which has a state income tax
1 answer:
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Answer:
A quarter of one lap of the track.
Step-by-step explanation:
Three students ran ran a relay and took turns running equal parts of the track.
The race was three-fourths of a lap long.
Let the length of one lap of the track=x
The length of the race
Since each of the students ran equal part,
Length run by each student
Therefore, each student ran a quarter of one lap of the track.
We take the function as a sequence
Term 1 ⇒ 5
Term 2 ⇒ 4
Term 3 ⇒ 3.2
Between terms, there is a common ratio of ⁴/₅
We get it from here:
Term 2 / Term 1 =
Term 3 / Term 2 =
=
When a sequence has a common ratio between term, the sequence is a Geometric Sequence
Where
is the first term, 
is the common ratio, and 
is the term number
We have:
and 
The formula for the function is
Term 1 ⇒ 5
Term 2 ⇒ 4
Term 3 ⇒ 3.2
Between terms, there is a common ratio of ⁴/₅
We get it from here:
Term 2 / Term 1 =
Term 3 / Term 2 =
When a sequence has a common ratio between term, the sequence is a Geometric Sequence
Where
We have:
The formula for the function is
Answer:
a) A sample of 256 was used in this survey.
b) 45.14% probability that the point estimate was within ±15 of the population mean
Step-by-step explanation:
This question is solved using the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
a. How large was the sample used in this survey?
We have that . We want to find n, so:
A sample of 256 was used in this survey.
b. What is the probability that the point estimate was within ±15 of the population mean?
15 is the bounds with want, 25 is the standard error. So
Z = 15/25 = 0.6 has a pvalue of 0.7257
Z = -15/25 = -0.6 has a pvalue of 0.2743
0.7257 - 0.2743 = 0.4514
45.14% probability that the point estimate was within ±15 of the population mean