2 years ago

Can plz help iam new

1 answer:

3 0

184 cubes difference

Explanation:

First guy made a 2x2x2 (L x W x H)
L: 2 x 2 = 4 ( twice as long)
W: 2 x 3 = 6 ( three times as wide)
H: 2 x 4 = 8 ( four times as high)

New block:

4 x 6 x 8 = 192

192 - 8 = 184 cubes different

You might be interested in

Find the equation of the line with the slope 3 that passes through (2,2)

Shkiper50 [21]

Answer : y = 3x - 1/2

7 0

2 years ago

Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack

vladimir1956 [14]

I believe its 5 bags, 1 granola bar in each bag and 2 pieces of fruit in each bag.

8 0

2 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

8 0

2 years ago

What is the nth term of this sequence?

lions [1.4K]

Answer:

D, you simply just add 1.3 each time.

4 0

2 years ago

Simplify -|-5 + 2|. A.-7 B.-3 C.3 D.7

larisa86 [58]

You're answer is (B).-3.

-|-5+2|

-5+2=-3

=|-3|

=-3

5 0

2 years ago