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irinina [24]
4 years ago
5

Write as an expression and simplify:

Mathematics
1 answer:
Bad White [126]4 years ago
5 0

Answer:

(a) The product of the sum of a and b and their difference.

(a+b)\times{(a-b)}\\=a^2-b^2

(b) The tripled product of 6a and b².

3(6a\times{b^2})\\=3(6ab^2)\\=18ab^2

(c) The difference of the squares of 2m and 7n.

(2m)^2-(7n)^2\\=4m^2-49n^2

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There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

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Multiply the number of boxes time the pencils in each box

5j

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