<span>H(t) = −16t^2 + vt + s
</span>
<span>H(t) = −16t^2 + 100t + 140
H(t) = 0 = </span><span>−16t^2 + 100t + 140
16t^2 - 100t -140 = 0
t = [100 +/- √ (100^2 -4(16)(-140) ) ] /(2(16))
t = 7.43 and t = - 1.18.
El que tiene sentido para la pregunta es t = 7.43 s.
Option B) 7 s (approximately)
</span>
Slope= 2/3
Explanation- adding 6y on both sides and subtracting 12 on both sides of eq, 12 + 6y -12=4x+6y-6y-12
6y = 4x-12
Divide by 6 on both sides of eq, we get y=4/6 x -12/6
y=2/3 x-2
D because you need to make the denominators have a common multiple.
The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
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is the slope between these two points. To figure out the slope between two points, we need to find the rise over run, which is the change in the <em>y value over the change in the x value</em>. This becomes:
And simplifies to:
, meaning that the slope between these two points is
.
