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Annette [7]
3 years ago
12

Jasper has 7 more checkers left than Karen does.Jaspar has 9 checkers left. write and solve an addition equation to find out how

many checkers Karen has left.
Mathematics
2 answers:
Hitman42 [59]3 years ago
8 0

Solution:

As per the problem we have

Jasper has 7 more checkers left than Karen does.

Let Karen has x checkers.

It mean Jasper has (x+7) checkers.

Now again from the problem we have

Jasper has 9 checkers left.

so we can write

x+7=9\\ \\ x=9-7\\ \\ x=2\\

It mean karen has 2 checkers left.

dimulka [17.4K]3 years ago
8 0
Well u just do 9+-7=2 checkers so Karen has 2 checkers left
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hodyreva [135]

Answer:

Question #1 choice A x=3, ST=24 and Question #2 choice C x =12

Step-by-step explanation:

Question #1

T midpoint so ST=TU and 8x = 2x+18

8x =2x+18

8x-2x=18

6x=18

x=18/6

x=3

so ST= 8x=8*3=24

choice A

Question #2

M midpoint of AB so AM=MB and 4x+1=7x-35

4x+1=7x-35

1+35=7x-4x

36=3x

36/3=x

12=x

choice C

7 0
4 years ago
Help plss put it in simplest <br> form
Nataly_w [17]

Answer:

50/21

Step-by-step explanation:

10 times 5 and 7 times 3 (:

3 0
3 years ago
VN
navik [9.2K]

Answer:

£2,121.8

Step-by-step explanation:

Given the following;

Principal P = £2000

Rate r = 3%

Time t = 2 years

n = 1 (time of compounding)

Using the compound interest formula;

A = P(1+r)^t

A = 2000(1+0.03)^2

A = 2000(1.03)^2

A = 2000(1.0609)

A = 2,121.8

hence the amount that will be in his account after 2 years is £2,121.8

6 0
4 years ago
Given m<br> n, find the value of x and y<br> m<br> (7x+18)<br> (5x-6)<br> (3y+11)<br> n
Dmitry_Shevchenko [17]

Answer:

7x + 18 + 5x - 6 = 180 \\ 12x + 12 = 180 \\ 12x = 180 - 12 = 168 \\ x = 168 \div 12 =14 \\ 3y + 11 = 7x + 18 = 7 \times 14 + 18 \\ 3y + 11 = 98 + 18 = 116 \\ 3y = 116 - 11 = 105 \\ y = 105 \div 3 = 35

6 0
3 years ago
The arch beneath a bridge is​ semi-elliptical, a​ one-way roadway passes under the arch. The width of the roadway is 38 feet and
forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

\frac{x^2}{a^2}+\frac{y^2}{b^2}

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

a=\frac{38}{2}=19ft

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}

and we can simplify the equation, so we get:

\frac{x^2}{361}+\frac{y^2}{144}

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

\frac{y^{2}}{144}=1-\frac{x^{2}}{361}

y^{2}=144(1-\frac{x^{2}}{361})

we can add everything inside parenthesis so we get:

y^{2}=144(\frac{361-x^{2}}{361})

and take the square root on both sides, so we get:

y=\sqrt{144(\frac{361-x^{2}}{361})}

and we can simplify this so we get:

y=\frac{12}{19}\sqrt{361-x^{2}}

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

y=\frac{12}{19}\sqrt{361-(8)^{2}}

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0
3 years ago
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