All categories

3 years ago

Suppose the function shown below was expressed in standard form, v = a * x ^ 2 + bx + c What is the value of a?

Mathematics

2 answers:

kipiarov [429]3 years ago

5 0

Answer:

Step-by-step explanation:

The answer is 2=a

just got it correct on the quiz

Kazeer [188]3 years ago

4 0

Answer:

a = v / x ^ 2 - b / x - c / x ^ 2 :))))))

You might be interested in

What is the surface area of the triangular prism shown?

Luba_88 [7]

Answer:

Step-by-step explanation:

we need to find the surface area of the shapes before adding them together. the triangles are 6*4 and since there are two, we do not need to divide by 2. (normally to find the area of a triangle it is base times height divided by 2)

so the area of the triangles are 24 units. Next we have the outer rectangles. 7*5=35. Since there are 2, we multiply by 2. Last we have the middle rectangle. 7*6=42.

the whole equation would be: 24+70+42= 136

so your answer would be B: 136.

hope this helps :)

4 0

3 years ago

2,4,8,16 recursive form

AVprozaik [17]

Question

2,4,8,16 recursive form

Answer:

The first term is 2, and each term after that is twice the previous term, so the equations are:

a sub1 = 2

a sub n = 2a sub n-1, for n>1

8 0

3 years ago

If the units for x are feet and the units for a(x) are pounds per foot, what are the units for da/dx?

SOVA2 [1]

Change in a with respect to x
pounds per foot would be the unit
lb/ft

8 0

4 years ago

What multiplies to -29 and adds to 1

Margarita [4]

First set up equation
x times y=xy

so
xy=-29
and
x+y=1
subtract x from both sides
y=1-x
subsitute 1-x for y in first equation
x(1-x)=-29
distribute
x-x^2=-29
add x^2 to both sides
x=-29+x^2
subtract x from both sides
0=x^2-x-29
so we can use the quadratic formula to solve for x if the equation=0 and it is in ax^2+bx+c form so

if
ax+bx+c=0 then x= $\frac{ -b+/-\sqrt{b^2-4ac} }{2a}$ that means x= $\frac{ -b-\sqrt{b^2-4ac} }{2a}$ or x= $\frac{ -b-\sqrt{b^2-4ac} }{2a}$ so

x^2-x-29
a=1
b=-1
c=-29
$\frac{ -(-1)-\sqrt{-1^2-4(1)(-29)} }{2(1)}$ = $\frac{ +1-\sqrt{1^2-(-116)} }{2(1)}=\frac{ +1-\sqrt{1^2+116} }{2}=\frac{ +1-\sqrt{117} }{2}= \frac{1-10.816653826392}{2} = [tex] \frac{-9.816653826392}{2}= -4.908326913196$

the second number is
$\frac{ -(-1)+\sqrt{-1^2-4(1)(-29)} }{2(1)}=\frac{ +1+\sqrt{1^2+(-116)} }{2(1)}= \frac{1+10.816653826392}{2} = \frac{ +1+\sqrt{117} }{2}= \frac{10.816653826392}{2}=5.908326913196$

the two numbers are
5.908326913196 and
-4.908326913196

7 0

3 years ago

Find the indicated missing angle. Round to the nearest angle.

sladkih [1.3K]

Answer:

The missing angle 'x' is 22.29°.

i.e. $x\:=\:22.29^{\circ \:\:}$

Step-by-step explanation:

Let 'x' be the missing angle of the triangle.

Using the formula

tan x = opp ÷ adjacent

tan x = 30 ÷ 72

tan x = 0.41

$x=\tan ^{-1}\left(0.41\right)$

$x\:=\:22.29^{\circ \:\:}$

Therefore, the missing angle 'x' is 22.29°.

i.e. $x\:=\:22.29^{\circ \:\:}$

4 0

3 years ago