#1). The length of the whole circumference is (π · D) = 12π .
120° is 1/3 of 360°, so arc-AB is 1/3 of the whole circumference.
#2). 60° is 1/6 of 360°.
So arc-CD is 1/6 of the whole circumference (which is given).
#3). The circumference of the circle is (π·D) = 20π .
70° is (70°/360°) of the whole circle, so arc-XY
is (70/360) of the whole circumference.
#4). Sorry, I don't remember anything right now about
angles between chords.
I hope what I've given you so far is worth 5 points.
Subtract 15 from 7 and you get -8
So the answer is -8 degre C
Answer:
the surface area of the larger prism is or about 2.8 times the surface area of the smaller prism.
Answer: The side length of the square-shaped park is 120 meters.
Here we know that:
Here we Ann has two plots of land, one square and other triangular.
We know that the triangular one has an area of 32,500 m^2
And we also know that the total area is equal to 76,600 m^2
Then the area of the square plot will be equal to the difference between the total area and the area of the triangular plot.
area of the square plot = 76,600 m^2 - 32,500 m^2
Now, also remember that for a square of side length x, the area is given by:
A = x^2
Replacing that in the above equation we get:
x^2 = 76,600 m^2 - 32,500 m^2
Now we want to solve this for x, the side length of the square-shaped park.
First, let's solve the difference in the right side:
x^2 = 44,100 m^2
Now we can apply the square root in both sides to get:
√x^2 = √(44,100 m^2)
x = 210 m
The side length of the square-shaped park is 120 meters.
Step-by-step explanation:
