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Aleks [24]
4 years ago
13

At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr

om the account.Which explicit formula can be used to find the account’s balance at the beginning of year 14? What is the balance?
A.A(n) = (250)(n – 1)(0.03); $97.50 B.A(n) = 250 + (n)(0.03 • 250); $355.00 C.A(n) = 250 + (n – 1)(0.03); $250.39 D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
Mathematics
2 answers:
olganol [36]4 years ago
8 0

Answer:

the correct answer is D

Step-by-step explanation:

i just did it and it was right

Dennis_Churaev [7]4 years ago
4 0
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
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Step-by-step explanation:

Given:

The First term in the AP is -504

The Sum of its 9 terms is -126

To Find:

The sum of its 30 terms = ?

Solution:

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