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3 years ago

Which of these expressions are equivalent to −5+(2.5+315)⋅4.25 ? Choose the TWO correct answers.

Mathematics

1 answer:

qaws [65]3 years ago

4 0

Answer: A and D

Step-by-step explanation:because my teacher told me

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Sarah opens a savings account that has a 2.75% annual interest rate, compounded monthly. She deposits $500 into the account. How

qaws [65]

Answer: $754.94

Step-by-step explanation:

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3 0

3 years ago

The second derivative of acos(kx)

Shkiper50 [21]

F’(x)= -akxsinkx

F’’(x)= -a(kx)^2coskx

I’m really sorry if the answer turned out wrong but I tried my best!

8 0

2 years ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago

Find the values of x and y.

ValentinkaMS [17]

Answer:

x=110° y=140°

Step-by-step explanation:

x=180°-70°

x=110°

y=x+30°

y=110°+30°

y=140°

3 0

3 years ago

Hi, I need help with equations :D

lana [24]

3(3) - (-8)/4 = 9 + 2 = 11 so (3,-8) is solution

3(4) - 4/4 = 12 - 1 = 11 so (4,4) is solution

answer
C. both ordered airs are solutions

8 0

3 years ago