In ∆FTR, which side is included between ∠R and ∠F? A:RT B:TF C:FT D:RF
2 answers:
Answer: The correct option is (D). RF.
Step-by-step explanation: We are given to select the correct side that is included between the angles ∠R and ∠F in ΔFTR.
As shown in the attached figure, we have drawn triangle FTR.
Now, the side that is included between the angles ∠R and ∠F has endpoints at the vertices R and F.
So, we call that side as the side RF.
Therefore, the required side that is included between the angles ∠R and ∠F is the side RF.
Thus, (D) is the correct option.
You might be interested in
Problem 1
=========
Write an equation for line passing through (8,12) that is perpendicular to
y = (4/3)x - 5
Note:
When two lines are perpendicular, the product of their slopes is -1.
The slope of the given line is 4/3.
Therefore the slope of the perpendicular line is -3/4.
Let the equation of the perpendicular line be
y = -(3/4)x + c
Because the line passes through (8,12), therefore
-(3/4)*8 + c = 12
-6 + c = 12
c = 18
The equation is y = -(3/4)x +18
Answer:
Problem 2
=========
Write an equation for a line passing through (-30,7) that is perpendicular to
y = -3x - 5.
The perpendicular line will have a slope of 1/3. Let its equation be
y = (1/3)x + c
Because the line passes through (-30,7), therefore
(1/3)*(-30) + c = 7
-10 + c = 7
c = 17
The equation is y = (1/3)x + 17
Answer:
=========
Write an equation for line passing through (8,12) that is perpendicular to
y = (4/3)x - 5
Note:
When two lines are perpendicular, the product of their slopes is -1.
The slope of the given line is 4/3.
Therefore the slope of the perpendicular line is -3/4.
Let the equation of the perpendicular line be
y = -(3/4)x + c
Because the line passes through (8,12), therefore
-(3/4)*8 + c = 12
-6 + c = 12
c = 18
The equation is y = -(3/4)x +18
Answer:
Problem 2
=========
Write an equation for a line passing through (-30,7) that is perpendicular to
y = -3x - 5.
The perpendicular line will have a slope of 1/3. Let its equation be
y = (1/3)x + c
Because the line passes through (-30,7), therefore
(1/3)*(-30) + c = 7
-10 + c = 7
c = 17
The equation is y = (1/3)x + 17
Answer: