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Mekhanik [1.2K]
3 years ago
14

Given: AE is tangent of B. BC = 5 and AE = 24. What is the measure of EC?

Mathematics
2 answers:
Dmitry [639]3 years ago
6 0

Answer:

EC =26

Step-by-step explanation:

Because AE is tangent of B so BA ⊥ AE (one of the properties of a tangent line with a circle)

=> The triangle ACE is a right triangle

As given:

  • BC = 5 => AC = 10 (the diameter of the circle)
  • AE = 24

Use the pytagon theorem to find EC

EC^{2} = AC^{2} + AE^{2}

= 10^{2} + 24^{2}

= 676

<=> EC = \sqrt{676} = 26

cluponka [151]3 years ago
4 0
26. 
You can solve this using the Pythagorean Theorem. The length of AC = 10 and the length of AE = 24. These are your two legs. Square both and then add them together. Then take the square root to get your answer. 
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