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2 years ago

What is the answer to 7/2

Mathematics

2 answers:

SashulF [63]2 years ago

8 0

Your correct answer would be 3.5

Mariana [72]2 years ago

3 0

3.5 is the correct answer.

You might be interested in

What are the coordinates of the hole in the graph of the function f(x)?

jonny [76]

Answer:

The coordinates are (2,8)

Step-by-step explanation:

A hole is where both the numerator and the denominator are zero

f(x)=x^2+4x−12 / x−2

Factor the numerator

f(x) = (x+6) (x-2)/ (x-2)

The hole will occur where x-2 =0

x-2=0

Add 2 to each side

x-2+2 =0+2

x=2

There is a hole at x=2

If we could cancel the x-2 values from the top and bottom, we are left with

f(x) = x+6

At x=2

f(2) = 6+2

f(2) would be 8

The coordinates are (2,8)

There is a hole

8 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

5 0

3 years ago

You can afford a $1350 per month mortgage payment. You’ve found a 30 year loan at 7% interest.

Mice21 [21]

A) 45 because 1350 divide by 30 equals 45. So 45 dollars u can afford

B) 1350 because 45 x 30 = 1350

C) 7% because it’s 7% to begin with

4 0

3 years ago

The angles of a triangle are in the ratio 5:3:7 find the angles

omeli [17]

Answer:

60, 36, 84

Step-by-step explanation:

The angles of a triangle always add up to 180 degrees.

If the ratios are 5:3:7, that means that there are 15 pieces that we can break up the 180 degrees by.

180/15 = 12

Each value is 'worth' 12 degrees.

Thus the angles would be the ratios multiplied by 12.

5 x 12 = 60

3 x 12 = 36

7 x 12 = 84

3 0

3 years ago

What is 223 rounded to the nearest ten

ASHA 777 [7]

1. The number '2' is located in the tens place

2. Since the number '3' is located in the ones place, it's telling the number '2' to stay the same

Stays the Same: 1,2,3,4
Goes Up: 5,6,7,8,etc

223 ⇒ 220

4 0

3 years ago