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kondor19780726 [428]
2 years ago
8

How do you solve a TWO DIGIT BY THREE DIGIT DIVISION PROBLEM

Mathematics
2 answers:
Serjik [45]2 years ago
5 0
  150
x12

2x0 =0 2 times 5 is 10 you carry the one and 2x1=2 + the one you carried so its 3 now put those in order 300 now do 1 times 150 it would be 150 but when you multiply the last number you always put a zero in the ones place then the number so the answer would be 1500 plus 300= 1800 
1800 would be the answer
Mars2501 [29]2 years ago
4 0
First you have to know that the biggest number goes in the inside of the box and the small on the outside of the box. Then you see if that number can go into the inside number evenly. And if not you have to see how many times it can go into there then put it on top of the box over the number we used. Then subtract
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A(R+T)=W solve for T
Leni [432]
A(R+T)=W
(A×R)+(A×T)=W
AR+AT=W
-AR from both sides
AT=W-AR
divide both sides by A
T=(W-AR)/A
6 0
3 years ago
What is the area of a triangle with vertices (1,0) (5,0) (3,4)
Aleksandr-060686 [28]

Answer:

The area of the triangle is of 8 units of area.

Step-by-step explanation:

Answer:

The area of the triangle is of 21 units of area.

Step-by-step explanation:

The area of a triangle with three vertices (x_1,y_1),(x_2,y_2),(x_3,y_3) is given by the determinant of the following matrix:

A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|

In this question:

Vertices (1,0) (5,0) (3,4). So

A = \pm 0.5 \left|\begin{array}{ccc}1&0&1\\5&0&1\\3&4&1\end{array}\right|

A = \pm 0.5(1*0*1+0*1*3+1*5*4-1*0*3-0*5*1-1*1*4)

A = \pm 0.5*(20-4)

A = \pm 0.5*16 = 8

The area of the triangle is of 8 units of area.

3 0
3 years ago
(-1/9) ÷ 6/7 =<br><br> Help<br> Me<br> Pls<br> :)
german

Answer:

I believe your answer is -7/54

3 0
2 years ago
Read 2 more answers
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padilas [110]
It would be 2020-1836 = 184 years ago
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2 years ago
EZ 25 POINTS!!!!!
alexandr1967 [171]

Answer: 9

Step-by-step explanation:

4 0
2 years ago
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