3 years ago

How do you solve a TWO DIGIT BY THREE DIGIT DIVISION PROBLEM

2 answers:

5 0

150
x12

2x0 =0 2 times 5 is 10 you carry the one and 2x1=2 + the one you carried so its 3 now put those in order 300 now do 1 times 150 it would be 150 but when you multiply the last number you always put a zero in the ones place then the number so the answer would be 1500 plus 300= 1800
1800 would be the answer

Mars2501 [29]3 years ago

4 0

First you have to know that the biggest number goes in the inside of the box and the small on the outside of the box. Then you see if that number can go into the inside number evenly. And if not you have to see how many times it can go into there then put it on top of the box over the number we used. Then subtract

You might be interested in

Explain how you decide which part of a problem will be represented by the variable x, and which part will be represented by the

jok3333 [9.3K]

Well i don't know if this will help but slope intercept form

y=mx+b

M-slope
B-Y intercept
and
(x,y)- would be any point on the graph and if you were to plug those points in for x and y the equation would solve if done properly

6 0

3 years ago

Choose the answer. 3. (1 pt) Which is an example of the distributive property? A. 9 • (t + 5) = 9t + 45 B. 9 • (t + 5) = (t + 5)

saw5 [17]

The answer is A. this is because your are multiplying by 9 throughout

5 0

3 years ago

Read 2 more answers

Let U be a universal set with subsets A and B such that n(U)=118, n(A)=57, n(B′)=69, and n(A∩B)=11. Find the following:

Arturiano [62]

$n(B)=n(U)-n(B')=118-69=49\\
n(A\cup B)=n(A)+n(B)-n(A\cap B)=57+49-11=95\\
n((A\cap B)')=n(U)-n(A\cap B)=118-11=107$