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kvv77 [185]
3 years ago
8

Triangle KLM is translated to units right and one unit up to create triangle KLM which rule describes the transformation

Mathematics
1 answer:
Kazeer [188]3 years ago
3 0
Translation transformation
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PLEASE HELP AND SHOW WORK!!
aivan3 [116]
> multiply the second equation by 2 and add it to the first equation.
2(-6x - 7y = -10)
-12x -14y = -20

8x + 14y = 4
-12x - 14y = -20
--------------------
- 4x + 0 = - 16
x = -16/-4
x = 4

> use x = 4 in either equation to find y
8(4) + 14y = 4
32 + 14y = 4
14y = 4 - 32
14y = -28
y = -28/14
y = -2


5 0
3 years ago
Read 2 more answers
Solve the simultaneous equation 2p - 3q = 4, 3p + 2q = 9. <br>b. if 223= 87 find x<br>​
wolverine [178]

Answer:

Step-by-step explanation:

Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.

2p - 3q = 4 ...................... 1 * 3

3p + 2q = 9 ..................... 2 * 2

Multiplying equation 1 by 3 and 3 by 2:

6p - 9q = 12

6p + 4q = 18

Subtracting both equation

-9q-4q = 12-18

-13q = -6

q = -6/-13

q = 6/13

Substituting q = 6/13 into equation 2

2p - 3(6/13) = 4

2p - 18/13 = 4

2p = 4+18/13

2p = (52+18)/13

2p = 70/13

p = 70/26

p = 35/13

<em>Hence p = 35/13 and q = 6/13</em>

<em></em>

<em>b) </em>If if 223ₓ = 87 find x

Using the number base system and converting 223ₓ  to base 2 will give us;

223ₓ = 2*x² + 2*x¹ + 3*x⁰

223ₓ  = 2x²+2x+3

​

Substituting back into the equation, 2x²+2x+3 = 87

2x²+2x+3-87 = 0

2x²+2x-84 = 0

x²+x-42 = 0

On factorizing:

(x²+6x)-(7x-42) = 0

x(x+6)-7(x+6) = 0

(x+6)(x-7) = 0

x+6 = 0 and x-7 = 0

x = -6 and 7

<em>Hence the value of x is 7 (neglecting the negative value)</em>

5 0
3 years ago
Uagsusvs CBA CBA read
SOVA2 [1]
Im not sure but CBA i think it has to do with some bank
4 0
3 years ago
Simplify 1.25 (-x -4)
statuscvo [17]

Answer:

1.25(-xsquare - 8x + 16)

Step-by-step explanation:

pls give me brainliest

I'm not sure but I think so

3 0
2 years ago
Will mark brainliest!!!plz helppp
muminat

Answer:

(5,-6)

Step-by-step explanation:

ONE WAY:

If f(x)=x^2-6x+3, then f(x-2)=(x-2)^2-6(x-2)+3.

Let's simplify that.

Distribute with -6(x-2):

f(x-2)=(x-2)^2-6x+12+3

Combine the end like terms 12+3:

f(x-2)=(x-2)^2-6x+15

Use (x-b)^2=x^2-2bx+b^2 identity for (x-2)^2:

f(x-2)=x^2-4x+4-6x+15

Combine like terms -4x-6x and 4+15:

f(x-2)=x^2-10x+19

We are given g(x)=f(x-2).

So we have that g(x)=x^2-10x+19.

The vertex happens at x=\frac{-b}{2a}.

Compare x^2-10x+19 to ax^2+bx+c to determine a,b,\text{ and } c.

a=1

b=-10

c=19

Let's plug it in.

\frac{-b}{2a}

\frac{-(-10)}{2(1)}

\frac{10}{2}

5

So the x- coordinate is 5.

Let's find the corresponding y- coordinate by evaluating our expression named g at x=5:

5^2-10(5)+19

25-50+19

-25+19

-6

So the ordered pair of the vertex is (5,-6).

ANOTHER WAY:

The vertex form of a quadratic is a(x-h)^2+k where the vertex is (h,k).

Let's put f into this form.

We are given f(x)=x^2-6x+3.

We will need to complete the square.

I like to use the identity x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2.

So If you add something in, you will have to take it out (and vice versa).

x^2-6x+3

x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2

(x+\frac{-6}{2})^2+3-3^2

(x+-3)^2+3-9

(x-3)^2+-6

So we have in vertex form f is:

f(x)=(x-3)^2+-6.

The vertex is (3,-6).

So if we are dealing with the function g(x)=f(x-2).

This means we are going to move the vertex of f right 2 units to figure out the vertex of g which puts us at (3+2,-6)=(5,-6).

The y- coordinate was not effected here because we were only moving horizontally not up/down.

3 0
3 years ago
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