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Levart [38]
3 years ago
8

Solve the equation g+4/g-2 = g-5/g-8

Mathematics
1 answer:
Rudiy273 years ago
7 0
The answer of the above equation value of g = 22/3
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First to answer gets brainliest
skad [1K]

Answer:

Step-by-step explanation:

Because you can't do -x+1 so it would be (1,0) and then you have x^2 +3x-4 which is (-5,6)

6 0
3 years ago
Simply (8xto4) (4x to 3) \ 7x to 2
Anon25 [30]
32x^5/7 This is the answer for that equation.
4 0
4 years ago
!!!Please help!!!<br><br> (See attachment)
Marrrta [24]

Answer:

Given in figure ABCD:

∠ABD≅∠CBD

AB≅CB

To prove:

∠A≅∠C

Solution:

In the figure ABCD, we will first prove the Δ ABD and Δ CBD are congruent.

Thus the proof can be given as:

Statement                  Reason

1) \angle ABD \cong \angle CBD    Given

2) AB\cong CB             Given

3) BD\cong BD       Reflexive property of congruence (As the segment                                          is congruent to itself)

4) \triangle ABD\cong \triangle CBD    S.A.S (Side Angle side)

5) \angle A\cong \angle C   Corresponding parts of congruent triangles are congruent.

Hence proved.

7 0
4 years ago
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Vlada [557]
The answer would be 9/20 I think.

5 0
3 years ago
Help plsss
LenKa [72]
<h3></h3><h2>⭐ Development:</h2><h3></h3>

  • Having the expression, let's modify it so it becomes a 2nd degree equation:

\large {\text {$ \sf \cfrac{1}{2x^2} -2 = 0 $}}

  • Now, we will multiply per 2x² both sides of equation...

\large {\text {$ \sf \cfrac{1}{2x^2}\cdot \:2x^2-2\cdot \:2x^2=0\cdot \:2x^2 $}

                 \searrow

                     \large {\text {$ \sf 1-4x^2=0$}}

  • We have to write in standard form...

\large {\text {$ \sf -4x^2+1 = 0 $}}

<u>                                                                                                      </u>

<u />

\large {\text{$\sf x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2a} \quad\rightarrow\quad x=\cfrac{-0\pm\sqrt{0^2-4\cdot (-4) \cdot1} }{2\cdot (-4) } \:\rightarrow\:\: x=\cfrac{-0^2 \pm4}{2 \cdot(-4)}    $}}  

                                                                                                                         

                                                             \huge {\text {$ \sf \downarrow$}}

                                                                                                         

           \large {\text {$\sf {\bf x_1} = \cfrac{-0+4}{2\left(-4\right)}= \cfrac{-1}{2}  $}}                        \large {\text {$\sf {\bf x_2 }=\cfrac{-0-4}{2\left(-4\right)} = \cfrac{1}{2}  $}}

  • At this point, we're going to add the values ​​of x₁ and x₂:

\large {\boxed {\boxed { \bf x_1 + x_2=  -\cfrac{1}{2}+ \cfrac{1}{2} = 0}  }}

                                           \huge {\text {$ \it  Alternative \: A $}}

8 0
3 years ago
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