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4 years ago

A recipe for quinoa calls 2 2/3 cups of milk. Conner wants to makes 4 batches of quinoa. How much milk does he needs

Mathematics

2 answers:

krek1111 [17]4 years ago

8 0

10 2/3 cups of milk for 4 batches

allochka39001 [22]4 years ago

4 0

Answer:

Step-by-step explanation:

We multiply 4 x 2 2/3.

First, we multiply the 2 whole into the denominator 3. and we get the answer 6.

We then add 2, or the numerator. Forming 8/3. an improper fraction.

Now, we multiple the 4 batches, to 8/3. But we don't need to multiply the denominator this time.

So now that we have 32/3, again an improper fraction. We can divide.

Lastly we divide it. so 32 ÷ 3 = 10 2/3.

So the answer is 10 2/3 cups of milk.

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(1 point) 6 cards are drawn at random without replacement from a standard deck. Be accurate to 7 decimal places. a) Find the pro

V125BC [204]

Answer:

a) P=0.0000843

b) P=0.0000454

c) P=0.0066113

Step-by-step explanation:

6 cards are drawn at random without replacement from a standard deck.

a) We calculate the probability that all the cards are hearts.

We calculatethe number of possible combinations:

$C^{52}_6=\frac{52!}{6!(52-6)!}=20358520$

We calculate the number of favorable combinations:

$C_6^{13}=\frac{13!}{6!(13-6)!}=1716$

Therefore, the probability is

$P=\frac{1716}{20358520}\\\\P=0.0000843$

b) We calculate the probability that all the cards are face cards.

We calculatethe number of possible combinations:

$C^{52}_6=\frac{52!}{6!(52-6)!}=20358520$

We calculate the number of favorable combinations:

$C_6^{12}=\frac{12!}{6!(12-6)!}=924$

Therefore, the probability is

$P=\frac{924}{20358520}\\\\P=0.0000454$

c) We calculate the probability that all the cards are even.

We calculatethe number of possible combinations:

$C^{52}_6=\frac{52!}{6!(52-6)!}=20358520$

We calculate the number of favorable combinations:

$C_6^{24}=\frac{24!}{6!(24-6)!}=134596$

Therefore, the probability is

$P=\frac{134596}{20358520}\\\\P=0.0066113$

7 0

3 years ago

In ΔLMN, l = 8.7 cm, m = 2.3 cm and n=6.6 cm. Find the measure of ∠M to the nearest degree.

DIA [1.3K]

Answer:

Step-by-step explanation:

\underline{\text{Solution Method 2:}}

Solution Method 2:

Use original formula

a^2=b^2+c^2-2bc\cos A

−2bccosA

From reference sheet.

\text{Since we are finding }\angle M\text{,}

Since we are finding ∠M,

\text{plug in }2.3\text{ for side }a:

plug in 2.3 for side a:

Opposit the angle we want

2.3^2 = 6.6^2+8.7^2-2(6.6)(8.7)\cos M

2.3

=6.6

+8.7

−2(6.6)(8.7)cosM

Plug in values. Side "a" is opposite the wanted angle.

5.29 = 43.56+75.69-114.84\cos M

5.29=43.56+75.69−114.84cosM

Square sides.

5.29 =

5.29=

\,\,\color{white}{-} 119.25-114.84\cos M

−119.25−114.84cosM

Add.

-119.25=

−119.25=

\,\,-119.25

−119.25

-113.96=

−113.96=

\,\,-114.84\cos M

−114.84cosM

\frac{-113.96}{-114.84}=\cos M

−114.84

−113.96

=cosM

Divide to solve for cos(A).

M= \cos^{-1}(\frac{-113.96}{-114.84})\approx7.098\approx 7^{\circ}

M=cos

−1

(

−114.84

−113.96

)≈7.098≈7

∘

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