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yKpoI14uk [10]
2 years ago
12

Okkkkkkk jjjjjjjjhhhhh

Mathematics
1 answer:
JulsSmile [24]2 years ago
5 0
Okkkkkkkkkkkkkkkkkkkkkkkkkkk
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The square of a positive number increased by twice the number equals three. Find the number
koban [17]

Answer:

1

Step-by-step explanation:

Let the number be x

x² + 2x = 3

x² + 2x - 3 = 0

Product  = -3

Sum =2

Factors = 3 * (-1)

x² + 3x - x - 3 = 0

x*(x+3) - (x + 3) = 0

(x + 3)(x - 1) = 0

Ignore x + 3 because the number is a positive number

x - 1 = 0

x = 1

The number is 1

8 0
3 years ago
PLEASE HELP A flight across the US takes longer east to west then it does west to east. This is due to the plane having a headwi
il63 [147K]
To solve our questions, we are going to use the kinematic equation for distance: d=vt
where
d is distance 
v is speed  
t is time 

1. Let v_{w} be the speed of the wind, t_{w} be time of the westward trip, and t_{e} the time of the eastward trip. We know from our problem that the distance between the cities is 2,400 miles, so d=2400. We also know that the speed of the plane is 450 mi/hr, so v=450. Now we can use our equation the relate the unknown quantities with the quantities that we know:

<span>Going westward:
The plane is flying against the wind, so we need to subtract the speed of the wind form the speed of the plane:
</span>d=vt
2400=(450-v_{w})t_{w}

Going eastward:
The plane is flying with the wind, so we need to add the speed of the wind to the speed of the plane:
d=vt
2400=(450+v_{w})t_{e}

We can conclude that you should complete the chart as follows:
Going westward -Distance: 2400 Rate:450-v_w Time:t_w
Going eastward -Distance: 2400 Rate:450+v_w Time:t_e

2. Notice that we already have to equations:
Going westward: 2400=(450-v_{w})t_{w} equation(1)
Going eastward: 2400=(450+v_{w})t_{e} equation (2)

Let t_{t} be the time of the round trip. We know from our problem that the round trip takes 11 hours, so t_{t}=11, but we also know that the time round trip is the time of the westward trip plus the time of the eastward trip, so t_{t}=t_w+t_e. Using this equation we can express t_w in terms of t_e:
t_{t}=t_w+t_e
11=t_w+t_e equation
t_w=11-t_e equation (3)
Now, we can replace equation (3) in equation (1) to create a system of equations with two unknowns: 
2400=(450-v_{w})t_{w}
2400=(450-v_{w})(11-t_e) 

We can conclude that the system of equations that represent the situation if the round trip takes 11 hours is:
2400=(450-v_{w})(11-t_e) equation (1)
2400=(450+v_{w})t_{e} equation (2)

3. Lets solve our system of equations to find the speed of the wind: 
2400=(450-v_{w})(11-t_e) equation (1)
2400=(450+v_{w})t_{e} equation (2)

Step 1. Solve for t_{e} in equation (2)
2400=(450+v_{w})t_{e}
t_{e}= \frac{2400}{450+v_{w}} equation (3)

Step 2. Replace equation (3) in equation (1) and solve for v_w:
2400=(450-v_{w})(11-t_e)
2400=(450-v_{w})(11-\frac{2400}{450+v_{w}} )
2400=(450-v_{w})( \frac{4950+11v_w-2400}{450+v_{w}} )
2400=(450-v_{w})( \frac{255011v_w}{450+v_{w}} )
2400= \frac{1147500+4950v_w-2550v_w-11(v_w)^2}{450+v_{w}}
2400(450+v_{w})=1147500+2400v_w-11(v_w)^2
1080000+2400v_w=1147500+2400v_w-11(v_w)^2
(11v_w)^2-67500=0
11(v_w)^2=67500
(v_w)^2= \frac{67500}{11}
v_w= \sqrt{\frac{67500}{11}}
v_w=78

We can conclude that the speed of the wind is 78 mi/hr.
6 0
3 years ago
7-8th grade math level
Ne4ueva [31]

Answer: Let me try to figure this out but this is not 7-8 grade math level

Step-by-step explanation:

7 0
2 years ago
1. P(x)=x^2+2<br> 2. P(x)= 2x +10
ruslelena [56]

Answer:

see explanation

Step-by-step explanation:

Since p(x) = x² + 2 , if x ≤ 4

For x = 4 then this is included in the inequality x ≤ 4

whereas x > 4 does not include x = 4 but values greater than 4

Thus to evaluate x = 4 use p(x) = x² + 2

4 0
3 years ago
Find the slope of the line that passes through the points (2,5) and (-8,5).
balu736 [363]
Y₂-y₁
--------
x₂-x₁

=

5-5
--------
-8-2

0
-----
-10

slope = 0
3 0
3 years ago
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