Paul wants to write equations in the form y=mx+b for the lines passing through point D that are parallel and perpendicular to li
ne h. First he finds the slopes of these two lines. What could he do next to find the y-intercepts?
2 answers:
You might be interested in
Answer:
y = -3x +2
Step-by-step explanation:
If you divide the equation for the given line by 2, it will be in slope-intercept form:
y = (1/3)x +7
This tells you its slope is 1/3. The slope of the perpendicular line is the negative reciprocal of this: -1/(1/3) = -3. The point-slope form of the equation for the perpendicular line can be written as ...
y = m(x -h) +k . . . . . line with slope m through point (h, k)
Your line is ...
y = -3(x -(-2)) +8
y = -3x +2
Answer:
x = 19
Step-by-step explanation:
To find the value of x, you set the equations as equal to each other:
Then you simplify: