Paul wants to write equations in the form y=mx+b for the lines passing through point D that are parallel and perpendicular to li
ne h. First he finds the slopes of these two lines. What could he do next to find the y-intercepts?
2 answers:
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Answer:
Angle 1 = Angle 2 = 5y -23 (Vertically opposite)
We can see that we have a triangle in the figure
Since the sum of all angles of a triangle is 180,
<em>(2x + 13) + (47) + (5y -23) = 180</em>
<em>2x + 5y + 37 = 180</em>
<em>2x + 5y = 143</em>
5y = 143 -2x -----------------(1)
Assuming l and m to be parallel
<em>angle 1 = 3x (corresponding angles)</em>
<em>5y - 23 = 3x </em>
<em>From equation (1)</em>
<em>143 -2x - 23 = 3x </em>
<em>120 = 5x </em>
x = 24 ---------------------- (2)
Using (2) in (1)
<em>5y = 143 - 2(24)</em>
<em>5y = 143 - 48</em>
<em>5y = 95</em>
y = 19
Therefore,
x = 24
y = 19
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