Area = side AB * side BC = (5x + 5x + 3)(3x + 92x - 4)
= (10x + 3)(95x - 4) = 950x^2 - 40x + 285x - 12
= 950x^2 + 245x - 12 Answer
This cannot be negative so restriction on x is 950x^2 + 245x > 12
That is x > 0.0421
Answer:
We are given that the two triangles are approximately equal or similar thus
angle M=angle Z = 124
angle L = angle X = 33
angle N= angle Y = ?
The total angles is 180, thus angle N or Y is 180- (124+33) = 23
You can do:
6x7000 then
6x300 then
6x80 then
6x1 then
you add all the product.
the answer 4,4286
Answer: The total number of different types of labels will the manufacturers have to produce = 24.
Step-by-step explanation:
Given: Choices for flavours = 4
Choices for sugar = 2 {either sugar or sugar free}
Choices for the qunatity = 3
By Fundamental counting principle,
Total number of different types of labels will have to produce = (Choices for flavors) x (Choices for sugar)x (Choices for the quantity )
= 4 x 2x 3
=24
Hence, the total number of different types of labels will the manufacturers have to produce = 24.
Answer:
Check the explanation
Step-by-step explanation:
Let X denotes steel ball and Y denotes diamond
= 1/9( 50+57+......+51+53)
=530/9
=58.89
= 1/9( 52+ 56+....+ 51+ 56)
=543/9
=60.33
difference = d =(60.33- 58.89)
=1.44
s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2
=31686/8 - 9/8( 3468.03)
=3960.75 - 3901.53
=59.22
s1 = 7.69
s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2
=33295/8 - 9/8 (3640.11)
=4161.875 - 4095.12
=66.75
s2 =8.17
sample standard deviation for difference is
s=![\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%28n1-1%29s_1%5E2%2B%20%28n2-1%29s_2%5E2%5D%2F%28n1%2Bn2-2%29%7D)
= ![\sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%289-1%29%2A59.22%2B%20%289-1%29%2A66.75%5D%2F%289%2B9-2%29%7D)
= 
=7.93
sd = 
=
=7.93* 0.47
=3.74
For 95% confidence level 
=1.96
confidence interval is
=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)
=(1.44 - 7.35 , 1.44 + 7.35)
=(-2.31, 8.79)
There is sufficient evidence to conclude that the two indenters produce different hardness readings.
