Step-by-step explanation:
A regular megagon is repr {1,000,000} and can be constructed as a truncated 500,000-gon, t{500,000}, a twice-truncated 250,000-gon, tt{250,000}, a thrice-truncated 125,000-gon, ttt{125,000}, or a four-fold-truncated 62,500-gon, tttt{62,500}, a five-fold-truncated 31,250-gon, ttttt{31,250}, or a six-fold-truncated 15,625-gon, tttttt{15,625}. A regular megagon has an interior angle of 179.99964°. The area of a regular megagon with sides of length a is given by
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Answer:
The enlargement ratio is 3:4
Step-by-step explanation:
We are given
a width of 16 units and length of 12 units
so,
and
now, we can find enlargement ratio
we can use formula
enlargement ratio = (length)/(width)
now, we can plug values
now, we can simplify it
So,
The enlargement ratio is 3:4
Part A : y=$0.75m+$4.50
Part B : $8.25
The x intercept is when y=0
6x+0=-12
x=-2, now you have point A with coordinates (-2, 0)
The y intercept is when x=0
0+2y=-12
y=-6, so you have another point with coordinates (0, -6)
Connect those two points, you have your graph. It is a line.
