All categories

3 years ago

What’s the answer to this ?

Mathematics

1 answer:

Alexus [3.1K]3 years ago

5 0

Answer:

59.44 units²

Step-by-step explanation:

The area of each triangular section can be computed from the side length (5 units) and the central angle (72°) as ...

... section area = (1/2)sin(72°)·5² ≈ 12.5·0.951057 ≈ 11.8882 . . . units²

Then 5 such sections will have an area of ...

... pentagon area = 5·11.8882 units² = 59.4410 units²

_____

<em>Comment on central angle</em>

The central angles total 360°. There are 5 equal sections, so the central angle for each of them is 360°/5 = 72°.

<em>Comment on area formula</em>

It can be occasionally handy to know that the area of a triangle can be computed from the lengths of adjacent sides and the angle between them. The formula for sides of length "a" and "b" and angle β is ...

... A = (1/2)ab·sin(β)

You might be interested in

Solve these liner inequalities 2(x+1)>3(x-8)

raketka [301]

The answer for that problem is X<26

4 0

3 years ago

Write a fraction that is less than 1/3 using 1 as numerator

xenn [34]

1/6 is less than 1/3

3 0

3 years ago

In 2015 there were 759 laptops at lightning high school starting a 2016 the school box 75 more laptops at the end of each year t

nikdorinn [45]

Answer:

Step-by-step explanation:

Given the following :

Number of laptops in 2015 = 759

t(x) = 75x + 759 ; model to determine number of laptops at the school. X years after 2015.

Number of laptops in the school in 2020:

4 0

3 years ago

Sisters Lisa and Melissa want to share equally the cost of a $609 lap top computer. How much should each girl pay?

Natali5045456 [20]

Answer:

$304.5...........................

3 0

3 years ago

A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im

loris [4]

Answer:

Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).

As, DO is Dilation of Δ ABC by Scale factor of $\frac{1}{2}$ .

Vertices of A' B'C' are

$A'=(\frac{-4}{2},\frac{3}{2})=(-2,\frac{3}{2}), B'=(\frac{4}{2},\frac{4}{2})=(2,2), C'=(\frac{1}{2},\frac{1}{2})$

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.

The two triangles will be congruent.

AO is Dilated by a factor of half , so A'O' will be half of AO.

So, correct Statements are

1. AB is parallel to A'B'.

2.DO,1/2(x, y) =

The distance from A' to the origin is half the distance from A to the origin.

$OA=\sqrt{(-4)^2+3^2}=\sqrt{25}=5\\\\ O'A'=\sqrt{2^2+(\frac{3}{2})^2}=\frac{5}{2}=2.5$

8 0

3 years ago

Read 2 more answers