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goblinko [34]
3 years ago
7

Which one of you pieces of shxt is good at math

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer: it depends lolll

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
2 years ago
A circle has a diameter of 4 inches. A square has a side length of 4 inches. What is true about the areas of these two figures?
liubo4ka [24]
Answer:


The area of the square is greater than the area of the circle.
8 0
2 years ago
I need help plssss so yeh ill mark brainleist
padilas [110]

Answer:

2. \frac{1}{40}

4. \frac{5}{48}

6. \frac{1}{45}

8. \frac{1}{8}

10. \frac{1}{35}

12. \frac{3}{10}

14. \frac{11}{72}

16.\frac{5}{32}

4 0
2 years ago
Read 2 more answers
Y = 3/5х + 2 on a graph
Andrei [34K]

Answer:

Go to desmos graphing calculator and put your equation in and it will graph it for you I used it for my math questions like this

Step-by-step explanation:

HOPE THAT HELPS YOU

7 0
2 years ago
Find the difference . <br>6 3/5 - 4 3/10<br>A. 2 0/5 <br>B. 2 1/5<br>C. 2 3/10<br>D. 10 9/10
pochemuha
Make improper fractions.

33/5 - 43/10

Find a common denominator, in this case it is 10.

66/10 - 43/10 = 23/10

This can be simplified to 2  3/10

Hope this helps!
6 0
3 years ago
Read 2 more answers
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