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Evgen [1.6K]
2 years ago
12

What is the sum of 1 7/10 and 3 3/5?

Mathematics
2 answers:
Ksju [112]2 years ago
7 0

Answer:

5 3/10

Step-by-step explanation:

galina1969 [7]2 years ago
7 0

Answer:

5 3/10

-

You make the 3/5 into 6/10 and proceed with combining like terms

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A dime has the same value as 10 pennies. Marley brought 290 pennies to the bank. How many dimes did Narley get?
Oxana [17]
The answer is simply 290 pennies divided by 10 pennies per dime. The answer is 29 dimes.
5 0
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What is the diameter of the circle of its area is 325 ?
dalvyx [7]
The diameter of a circle that has an area of 325 is 20.34
5 0
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Read 2 more answers
There are 188 people on the trip and their total cost for the bike tour was $5040. There were twelve more adults than seniors on
zavuch27 [327]

Answer:

The answer to your question is there were 88 children

Step-by-step explanation:

Data

Total number of people = 188

total cost = $5040

12 more adults than seniors

number of children = ?

adults = a

children = c

Process

1.- Write equations that help to solve this problem

             a + c = 188              Equation l

             a = c + 12                 Equation ll

2.- Solve by substitution. Substitute equation equation ll in equation l

           (c + 12) + c = 188

-Solve for c

            c + 12 + c = 188

            2c + 12 = 188

            2c = 188 - 12

            2c = 176

              c = 176 / 2

              c = 88

3.- Conclusion

There were 88 children

       

5 0
3 years ago
Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 9 − x2 − y2 and the
Katyanochek1 [597]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
4 0
3 years ago
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