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otez555 [7]
3 years ago
11

How do you find the perimeter of a triangle?

Mathematics
1 answer:
vazorg [7]3 years ago
7 0
To find the perimeter<span> of a polygon, take the sum of the length of each side. The formula for </span>perimeter<span> of a triangle would be the sum of the three side lengths (a +b+c). In the case, where it is a regular polygon, the perimeter would be 3 times the side length. Hope this answers the question.</span>
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If a can of paint covers 300 sq. feet, how many cans must be purchased to paint a wall 20 feet by 50 feet?
Serhud [2]
You need 4 Or exactly 3 and 1/3 paint cans because the area would be 1000 feet
5 0
2 years ago
Plssss help mee
Bogdan [553]
The relationship is linear.

The reason why is because each time x increases by 1, the value of y increases by 3. In other words, the slope is 3 and it is constant no matter what two points you pick
x = input
y = output

------------------------------

Extra Info:
slope = rise/run
slope = (change in y)/(change in x)
slope = 3/1
slope = 3
The y intercept is (0,6). Think backwards in terms of the pattern going on. 
Or you can plug m = 3 and (x,y) = (1,9) into y = mx+b and solve for b to get b = 6
8 0
2 years ago
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Help I’m timed I’ll mark u brainliesttt
Zigmanuir [339]
It would be 5sqrt2

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4 0
3 years ago
A scuba diver descends 63 feet in 18 seconds.
Elanso [62]

Answer:

3.5

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5 0
3 years ago
Solve: <br>x + y = 7<br>3x - 2y = 11<br><br>By using Substituting method.​
Salsk061 [2.6K]

\large\underline{\sf{Solution-}}

\sf  \longmapsto x + y = 7 \: \: - - - (i)

\sf  \longmapsto 3x - 2y = 11 \: \: - - - (ii)

<u>By first equation,</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x = 7 - y

<u>Now, we can find the original value of y.</u>

\sf \longmapsto 3x - 2y = 11

\sf  \longmapsto 3(7 - y) - 2y = 11

\sf  \longmapsto 21 - 3y - 2y = 11

\sf  \longmapsto 21 - 5y = 11

\sf  \longmapsto - 5y = 11 - 21

\sf  \longmapsto - 5y =  - 10

\sf  \longmapsto y = \dfrac{ - 10}{ - 5}

\sf  \longmapsto y = 2

<u>Now, we can find the original value of x.</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x + 2 = 7

\sf  \longmapsto x = 7 - 2

\sf  \longmapsto x = 5

Therefore, the values of x and y are 5 and 2 respectively.

8 0
2 years ago
Read 2 more answers
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