Answer:
The correct answer will be option-D
Explanation:
Arid areas are the regions of the world which can be marked with the lack of water conditions, high light intensity and very low rainfall.
Water is one of the primary requirement of the plant without which no plant can survive but the adaptability to the environment allows the existence of the life on earth.
There are known species of plants which are adaptive to such arid conditions.
If a farmer is interested in growing plants in such arid conditions hen he should select the plants which could better be adapted to survive in the arid conditions either by avoiding arid condition like storing water, low transpiration, extensive root system and many others.
Thus, Option-D is the correct answer.
Answer:
Her perspective is compatible with: <u>Biopsychosocial</u> medical model.
Explanation:
This model refers to the connection of a medical model that involves three important aspects of a human life such as it's biologycal, psychological and social sides. The biological part has to do with her back pain. This is interfiering with her performance at work which has to do with the social aspects. The psychological aspect interferes with her being able to performe well.
Answer:
Omg HEYYY
Explanation:
great question. The #### ##### ######## ## ###
Answer:
0.50
Explanation:
According to the given information, the frequency of the hornless genotype in the population is = 16% = 0.16. This means that the frequency of the hornless allele in the population is = square root of 0.16 = 0.4.
The gene for the horns in unicorn has three alleles. If the frequency of the allele for twisted horns is represented by "p" and that of the hornless allele is represented as "q", then the frequency of the allele for the longhorn would be (r) = 1- (p+q).
This is due to the fact that the sum total of frequencies of all the possible alleles of a particular gene in a population in the Hardy Weinberg Equilibrium is always 1 (p+q+r =1). Now, putting the values of p and q in the formula to calculate the frequency of allele for the longhorn (r) = 1- (0.1 + 0.4) = 1-0.5 = 0.5
