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3 years ago

If 0.250 g of a gas sample represents 1.05x10–2 mol, what is the molar mass of the gas?

1 answer:

7 0

23.8 g/mol Since the definition of molar mass is mass per mole, just divide the mass of the sample by the number of moles you have. So 0.250 g / 1.05x10^-2 mol = 23.8095 g/mol Since our input data only has 3 significant figures, you need to round the result to 3 significant figures. 23.8095 g/mol rounds to 23.8 g/mol

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4. Describe what happens when:

lina2011 [118]

When two plates carrying oceanic crust collides, islands and volcanoes are formed.

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When a plate carrying oceanic crust collided with a plate carrying continental crust collides, the oceanic plate subsides under the continental one due to the density of the two, and makes trenches and mid-ocean ridges.

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3 years ago

(5points) Na2[Fe(OH2)2(OH)I3]absorbs photons with energy of 191kJ/mol. Calculate the wavelength (in nm) for a photon absorbed by

AfilCa [17]

Answer:

626.7nm

Explanation:

The energy of a photon is defined as:

E = hc / λ

Where E is the energy of the photon, h is Planck constant (6.626x10⁻³⁴Js), c is speed of light (3x10⁸m/s) and λ is the wavelength of light

The energy of 1 photon is:

(191000 J / mol) ₓ (1 mole / 6.022x10²³) = 3.1717x10⁻¹⁹ J

Replacing:

3.1717x10⁻¹⁹ J = 6.626x10⁻³⁴Jsₓ3x10⁸m/s / λ

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6 0

3 years ago

How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __

kiruha [24]

Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

determine the number of moles of HCl
determine the mole ratio,
use the mole ratio to calculate the number of moles of aluminum.
use RFM of Aluminum to determine the grams required.

Moles of HCl

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

$x \: mol \: = \: \frac{2 \: \times \: 35}{1000} \\ = 0.07 \: moles \:$

We have 0.07 moles of HCl.

Mole ratio

Balanced equation

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

but moles of HCl is 0.07, therefore the moles of Al;

$= \frac{2}{6} \times 0.07 \\ \: = 0.0233333 \: moles$

Therefore we have 0.0233333 moles of aluminum.

Grams of Aluminum

We use the formula;

$grams \: = moles \: \times \: rfm$

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

$= 0.0233333 \: moles \: \times \: 26.982 \: \frac{g}{mol} \\ = 0.625799 \: grams$

The number of grams of aluminum required to react with HCl is 0.6258 g.

3 0

2 years ago

A sample of oxygen gas has a volume of 150.0 ml when its pressure is .947 atm. what will the volume of the gas be if the tempera

joja [24]

D
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3 years ago

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Answer:

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3 years ago

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