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Serggg [28]
3 years ago
5

Identify the various types of fossil fuels helppp​

Chemistry
1 answer:
docker41 [41]3 years ago
8 0

Answer: hehe its kirishima here and the various types of fossil fuels are energy provision coal, oil and natural gas. Coal is a solid fossil fuel formed over millions of years by decay of land vegetation.

haha hope this helped

-yours truly red riot

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Using the periodic table, choose the more reactive metal. Ca or Ra
siniylev [52]
Radium is more reactive than calcium so Ra.
7 0
3 years ago
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Calculate the volume of chlorine molecules produced at room temperature and pressure, when 234g of sodium chloride are electroly
rewona [7]

The volume of chlorine molecules produced at STP would be 96 dm³.

<h3>Stoichiometric problem</h3>

Sodium chloride ionizes during electrolysis to produce sodium and chlorine ions as follows:

NaCl --- > Na^+ + Cl^-

This means that 1 mole of sodium chloride will produce 1 mole of sodium ion and 1 mole of chlorine ion respectively.

Recall that: mole = mass/molar mass

Hence, 234 g of sodium chloride will give:

                         234/58.44 = 4.00 moles.

Thus, the equivalent number of moles of chlorine produced by 234 g of sodium chloride will be 4 moles.

Recall that:

1 mole of every gas at Standard Temperature and Pressure = 24 Liters.

Hence:

4 moles of chlorine = 4 x 24 = 96 Liters or 96 dm³.

More on stoichiometric problems can be found here: brainly.com/question/14465605

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4 0
2 years ago
What type of hydrocarbon is 2-octene, and what about the structure allows 2-octene to be classified as this type of hydrocarbon?
12345 [234]

an alkene because there is a double bond

5 0
3 years ago
A compound is found to contain 42.88 % carbon and 57.12 % oxygen by weight. To answer the questions, enter the elements in the o
Ipatiy [6.2K]

Answer:

The empirical formule is CO

Explanation:

Step 1: Data given

Suppose the mass of a compound is 100 grams

Suppose the compound contains:

42.88 % C = 42.88 grams C

57.12 % O = 57.12 grams O

Molar mass C = 12.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles C = mass C / molar mass C

Moles C = 42.88 grams / 12.01 g/mol

Moles C = 3.57 moles

Moles O = 57.12 grams / 16.0 g/mol

Moles O = 3.57 moles

Step 3: Calculate the mol ratio

We divide by the smallest amount of moles

C: 3.57 moles / 3.57 moles = 1

O: 3.57 moles / 3.57 moles = 1

The empirical formule is CO

3 0
2 years ago
Can anything change solutions? Be<br> specific!
trasher [3.6K]
What kind of solutions?
4 0
2 years ago
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