Answer:
A. VG = 80
B. Broad sense heritability = 0.80
C. Narrow sense heritability = 0.30
D. Average yield = 430 Units
Explanation:
A. Given that
VA = 30
VD = 50
VI = assumed not available
Therefore
Total genetic variance (VG) = VA + VD
= 30 + 50
= 80
VG = 80
B. Given that
VP = 100
VG = 80
Broad sense heritability, H2 = VG/VP
= 80/100
= 0.80
C. Given that
VA = 30
VP = 100
Narrow sense heritability, h2 = VA/VP
=30/100
= 0.30
D. The difference in selection = 500 - 400
= 100
Recall,
Selection response is heritability multiplied by selection differential.
That is
R = h2S
Selection differential = 100
Heritability h2 = 0.30
Selection response = 0.30 × 100
= 30units
Therefore, expected average yield = 400 + 30
= 430 Units
<span>The closer you are to the poles of the Earth, the fewer ecological niches for species to fill. </span>
Answer:
GCC GTA TAT
Adenine pairs with guanine.
Cytosine pairs with thymine.
Hope it helps!
Extreme disturbances are complex events. The terminology used to identify them, such as 'hurricanes,' 'fires,' 'economic collapse,' 'war,' or 'drought,' is insufficient for advancing understanding about how they interact with, and affect, ecosystems, including SETS.
