For multiplying radical expressions, we are first to list down the given.
f(x) = (x + 3/x)^(1/2), and
g(x) = (x + 3/2x)^(1/2)
We take a look at first the values of the radicands, these are the numbers inside the radical signs. Since, both of the radicands are raised to exponent 1/2, it is easy to say that we just have to multiply them and raise the product to the exponent 1/2 as well. That is,
(f·g)(x) = ((x + 3/x)(x + 3/2x))^(1/2)
Simplifying,
(f·g)(x) = ((x² + 3/2 + 3 + 9/2x²)^(1/2))
Further simplification will lead us to the final answer of,
<em>(f·g)(x) = (x² + 9/2 + 9/2x²)^(1/2)</em>
Answer:
180
Step-by-step explanation:
because im always right
0.24 repeating so rounding it to the nearest hundredth would make it stay 0.24<span />
