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Anarel [89]
3 years ago
12

Can someone PLEASE solve this quadratic equation by factoring with the steps? :(

Mathematics
1 answer:
salantis [7]3 years ago
5 0

Answer:

There are no simple factors to this expression.  You can however solve for x, giving you:

x = -1 ± √(y + 3)

Step-by-step explanation:

There is no simple pair of factors to this equation, so we'll have to go through the full process.  You can see that by observing that there is no pair of rational numbers that add to make 2 and multiply to make -2.  We can however solve for x:

y = x^2 + 2x - 2\\y + 2 = x^2 + 2x\\y + 3 = x^2 + 2x + 1\\y + 3 = (x + 1)^2\\(x + 1)^2 = y + 3\\x + 1 = \pm \sqrt{y + 3}\\x = -1 \pm \sqrt{y + 3}

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1. A sample consists of 75 TV sets purchased several years ago. The replacement times of those TV sets have a mean of 8.2 years.
Greeley [361]

Answer:

8.2+/-0.25

= ( 7.95, 8.45) years

the 95% confidence interval (a,b) = (7.95, 8.45) years

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 8.2 years

Standard deviation r = 1.1 years

Number of samples n = 75

Confidence interval = 95%

z value(at 95% confidence) = 1.96

Substituting the values we have;

8.2+/-1.96(1.1/√75)

8.2+/-1.96(0.127017059221)

8.2+/-0.248953436074

8.2+/-0.25

= ( 7.95, 8.45)

Therefore the 95% confidence interval (a,b) = (7.95, 8.45) years

3 0
3 years ago
at the start of the shift your part counter reads 250 at the end of the shift the part counter reads 1075 how many parts did you
Luden [163]
This can be mathematically expressed to
 250 + X  = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825

You produced 825 parts in the middle of the shift.

5 0
3 years ago
Simplify expression (5xy^-6/x^4 y^-2)^2
ipn [44]
Here it is...........................

4 0
3 years ago
Observe
slega [8]

Answer:

They both have the same y-intercept

one is a straight line and the other is not

I used my brain to solve it.please mark me as the brainiest,It would mean a lot to me.

6 0
3 years ago
A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
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