Find the perimeter of rectangle PQRS with vertices P(0,0), Q(0,7), R(12,7) & S (12,0).
1 answer:
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Answer:
Probability that exactly 5 of them favor the building of the health center is 0.0408.
Step-by-step explanation:
We are given that in a recent survey, 60% of the community favored building a health center in their neighborhood.
Also, 14 citizens are chosen.
The above situation can be represented through Binomial distribution;
where, n = number of trials (samples) taken = 14 citizens
r = number of success = exactly 5
p = probability of success which in our question is % of the community
favored building a health center in their neighborhood, i.e; 60%
<em>LET X = Number of citizens who favored building of the health center.</em>
So, it means X ~
Now, Probability that exactly 5 of them favor the building of the health center is given by = P(X = 5)
P(X = 5) =
=
= 0.0408
Therefore, Probability that exactly 5 of them favor the building of the health center is 0.0408.
Answer:
The correct option is;
∠A ≅ ∠X
Step-by-step explanation:
The given coordinates of the points of triangle ACB are;
A(-4, 4), C(-1, 3), B(-4, 0)
The given coordinates of the points of triangle XYZ are;
X(0, 8), Y(8, 8), Z(6, 2), therefore, we have
The length. l. of segment is given by the following formula;
For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)
For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4
For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2
For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8
For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2
For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10
Therefore;
XY ~ AB, XZ ~ BC, ZY ~ AC
Which gives;
∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z
